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lapo4ka [179]
3 years ago
6

Fre.e points because you deserve it

Physics
2 answers:
bagirrra123 [75]3 years ago
5 0

Answer:

thank you so much.. i appreciate your kindness

Anarel [89]3 years ago
5 0

Answer:

THANK YOU

YUOR AWSOME

Explanation:

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\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Efficiency.

Here we can see that, the Input work is given as 2.2 x 10^7 J and the efficiency is given as 22%

The efficiency is => 22% => 22/100.

so we get as,

E = W(output) /W(input)

hence, W(output) = E x W(input)

so we get as,

W(output) = (22/100) x 2.2 x 10^7

=> W(output) = 0.22 x 2.2 x 10^7 => 0.484 x 10^7

hence, W(output) = 4.84 x 10^6 J

The useful work done on the mass is 4.84 x 10^6 J

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Interstellar space (far from any stars) contains atomic hydrogen (H) with a density of 1 atom/cm3 and at a temperature of about
Mandarinka [93]

Explanation:

Given that,

Number density n= 1\ atom/cm^{3} =10^{6}\ atom/m^3

Temperature = 2.7 K

(a). We need to calculate the pressure in interstellar space

Using ideal gas equation

PV=nRT

P=\dfrac{nRT}{V}

P=\dfrac{10^{6}\times8.314\times2.7}{6.023\times10^{23}}

P=3.727\times10^{-17}\ Pa

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The pressure in interstellar space is 36.78\times10^{-23}\ atm

(b). We need to calculate the root-mean square speed of the atom

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v_{rms}=\sqrt{\dfrac{3RT}{Nm}}

Put the value into the formula

v_{rms}=\sqrt{\dfrac{3\times8.314\times2.7}{1.007\times10^{-3}}}

v_{rms}=258.6\ m/s

The root-mean square speed of the atom is 258.6 m/s.

(c). We need to calculate the  kinetic energy

Average kinetic energy of atom

E=\dfrac{3}{2}kT

Where, k = Boltzmann constant

Put the value into the formula

E=\dfrac{3}{2}\times1.38\times10^{-23}\times2.7

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The kinetic energy stored in 1 km³ of space is 5.58\times10^{-23}\ J.

Hence, This is the required solution.

7 0
3 years ago
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