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Helga [31]
3 years ago
6

Question 5 of 10

Physics
1 answer:
spayn [35]3 years ago
4 0

Answer: A) 0.19 kg.m/s South just answered it right on Apex!

Explanation:

You might be interested in
Two coulombs of charge pass through a wire in 5 seconds. Calculate the current in the wire. 1​
gogolik [260]

Answer:

0.4A.

Explanation:

Current (A) = Charge (coulomb)/Time (secs)

2 coulombs/5 secs = 0.4A

7 0
2 years ago
A ball is thrown downward with an initial speed of 7 m / s. The ball's velocity after 3 seconds is m / s. (g = -9.8m / s²)
yan [13]

Answer:

-36.4 m/s

Explanation:

final velocity= initial velocity + acceleration x time

7 + (-9.8)(3)= -36.4 m/s

5 0
3 years ago
What is the ostrich's average acceleration from 9.0 to 18 seconds?
Sedaia [141]

The average acceleration from 9 to 18 seconds is 6 meters per second.

The graph shows that from 9 to 18 seconds the speed of the ostrich stays at a steady 6 meters per second.

6 0
3 years ago
Monochromatic light of a given wavelength is incident on a metal surface. However, no photoelectrons are emitted. If electrons a
mrs_skeptik [129]

Answer:

Light of a shorter wavelength should be used.

Explanation:

This is studied in the phenomenon called photoelectric effect, in which light is able to release electrons from a metal, said electrons are called photoelectrons .

The experiments that have been carried out show that <u>increasing  or decreasing the intensity of the light will not cause the photoelectrons to be emitted</u>, what will cause the photoelectrons to be emitted is to increase the frequency of the incident light.

And a higher frequency corresponds to a shorter wavelength according to the equation:

f=\frac{c}{\lambda}

(where f is frequency, c the speed of light, and \lambda the wavelength)

So the answer is that the wavelength of the light must be shortened to cause the emission of electrones.

4 0
3 years ago
Please help me with this question, especially the angle part. I have solved the initial velocity already. I don't know what to d
Helga [31]
I think you almost got it.

At the top, the velocity only has horizontal component, so v=12 m/s is v_x, which is v*cos(theta), because v_x is constant, so the same when it was launched or now.

With the value of the initial speed (28 m/s, which is the total speed), you can set

v_x = v * cos( theta ) ---> 12 = 28*cos(theta) --> cos(theta)=12/28=3/7

or theta = 64.62 deg, it is D. Think about it. I hope you see it.
5 0
3 years ago
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