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2 years ago

Question 5 of 10

Physics

1 answer:

spayn [35]2 years ago

4 0

Answer: A) 0.19 kg.m/s South just answered it right on Apex!

Explanation:

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A rocket has landed on Planet X, which has half the radius of Earth. An astronaut onboard the rocket weighs twice as much on Pla

Burka [1]

Explanation:

Let acceleration due to Gravity for a planet is given by:

$g_X=GM/R^2$

Here, $g_X = 2g$

Escape velocity is given by:

$v =\sqrt{ \frac{2GM} {R}} = \sqrt{2aR}$

Here, $R=R_earth/2$

and g_X = 2g

Therefore, $v=\sqrt(2(2g)(R/2))=v_0$

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2 years ago

Podocytes are also called<br> 1 poin

gulaghasi [49]

Visceral epithelial cells

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2 years ago

which of the following safety harnesses is the safest and most recommended when hunting from a treestand?

Lyrx [107]

The best tree stand safety harness is the Hunter Safety System Hybrid Flex Safety Harness, with its awesome ElimiShield Scent Control Technology.

Moreover, These stands are designed to be attached directly to the tree. Hunters using a fixed or suspended stand must choose a method of climbing up and down from the platform. The safest and most used method is sectional ladders.

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4 months ago

A weight of 30.0 N is suspended from a spring that has a force constant of 220 N/m. The system is undamped and is subjected to a

Nimfa-mama [501]

Answer:

$F_0 = 393 N$

Explanation:

As we know that amplitude of forced oscillation is given as

$A = \frac{F_0}{ m(\omega^2 - \omega_0^2)}$

here we know that natural frequency of the oscillation is given as

$\omega_0 = \sqrt{\frac{k}{m}}$

here mass of the object is given as

$m = \frac{W}{g}$

$\omega_0 = \sqrt{\frac{220}{\frac{30}{9.81}}}$

$\omega_0 = 8.48 rad/s$

angular frequency of applied force is given as

$\omega = 2\pi f$

$\omega = 2\pi(10.5) = 65.97 rad/s$

now we have

$0.03 = \frac{F_0}{3.06(65.97^2 - 8.48^2)}$

$F_0 = 393 N$

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2 years ago

The typical unit for a period used with Kepler's third law is

ollegr [7]

Well, if you're using the law to work with periods of Earth satellites,
then the most convenient unit is going to be 'hours' for the largest
orbits, or 'minutes' for the LEOs.

But if you're using it to work with periods of planets, asteroids, or
comets, then you'd be working in days or years.

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2 years ago