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3 years ago

This is the more to follow.

Mathematics

1 answer:

Nataliya [291]3 years ago

3 0

$\frac{6q}{20(q + r)}$

You can simplify this expression by dividing the top and bottom by 2

$\frac{6q}{20(q + r)}$ becomes $\frac{3q}{10(q + r)}$

$\frac{3q}{10(q + r)}$ is your answer

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3 years ago

Quanto é 60 x 11 + 346²

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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The probability of an event - picking teams. About (a) 10 kids are randomly grouped into an A team with five kids and a B team w

LuckyWell [14K]

Answer: The required probability is $\dfrac{4}{9}$

Step-by-step explanation:

Since we have given that

Number of kids = 10

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Number of kids in Team B = 5

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So, number of favourable outcome is given by

$2(\dfrac{8!}{3!\times 5!})$

Total number of outcomes is given by

$\dfrac{10!}{5!\times 5!}$

So, the probability that Alex ends up on the same team with at least one of his two best friends is given by

$\dfrac{2(\dfrac{8!}{5!\times 3!)}}{\dfrac{10!}{5!\times 5!}}\\\\=2\times \dfrac{8!}{3!}\times \dfrac{5!}{10!}\\\\=\dfrac{4}{9}$

Hence, the required probability is $\dfrac{4}{9}$

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3 years ago