Answer:
<h2>Heterogeneous</h2>
Explanation:
<h3><em>Milk </em><em>seems</em><em> to</em><em> be</em><em> </em><em>homogeneous</em><em> mixture</em><em> </em><em>but </em><em>actually</em><em> </em><em>milk </em><em>is </em><em>a </em><em>heterogeneous</em><em> </em><em>mixture</em><em> </em><em>and </em><em>a </em><em>colloid</em><em> </em><em>solution</em><em>.</em></h3>
Analiza Z drugiej zasady Newtona przyłożona siła wynosi 1 N F = ma = m (6 g) = (90 kg) (6x9,81 m / s) 5297 N I kg m / s?
Answer : The moles of 
are, 2.125 mole.
Explanation : Given,
Molarity of = 8.500 M
Volume of solution = 250 mL = 0.250 L (1 L = 1000 mL)
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the moles of are, 2.125 mole.
Answer:
187.34 atm
Explanation:
From the question,
PV = nRT.................. Equation 1
Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.
make P the subject of the equation
P = nRT/V.............. Equation 2
n = mass(m)/molar mass(m')
n = m/m'............... Equation 3
Substitute equation 3 into equation 2
P = (m/m')RT/V............ Equation 4
Given: m = 46 g, T = 25°C = (25+273) = 298 K, V = 3.00 L
Constant: m' = 2 g/mol, R = 0.082 atmL/K.mol
Substitute these values into equation 4
P = (46/2)(0.082×298)/3
P = (23×0.082×298)/3
P = 187.34 atm
