Answer:
c
Explanation:
igneous, sedimentary, and metamorphic. igneous forms from molten rock cools and solidifides
Answer: 0.745 g of 
will be produced from 1.08 g of sodium sulfate
Explanation:
To calculate the moles :
is the limiting reagent as it limits the formation of product and 
is the excess reagent.
According to stoichiometry :
3 moles of produce = 3 moles of
Thus 0.0076 moles of will require=
of
Mass of 
Thus 0.745 g of will be produced from 1.08 g of sodium sulfate
24.0mm^3=24÷10÷10÷10cm^3
density=Mass÷Volume
<h2>
Answer: 6 moles</h2>
<h3>
Explanation:</h3>
3 H₂ + N₂ → 2 NH₃
↓ ↓
4 mol 3 mol
Since the moles of N₂ is the smaller of the two reactants, then N₂ is the limiting factor (the reactant that will decide how much ammonia is produced since it has the smaller amount of moles). ∴ we have to use it in calculating the number of moles of ammonia
The mole ratio of N₂ to NH₃ based on the balanced equation is 1 to 2.
∴ the moles of NH₃ = moles of N₂ × 2
= 3 moles × 2
= 6 moles
