Answer:
66.85 m
Explanation:
We are given that
Acceleration ,a=
Speed of truck, v=9.5 m/s
We have to find the distance beyond which the traffic signal will the automobile overtake the truck.
Initial speed of automobile, u=0
We know that
Using the formula
For constant speed
Acceleration, a=0
Again
Substitute the value of t
Hence, the distance beyond which the traffic signal will the automobile overtake the truck=66.85 m
<h3><u>Given</u><u>:</u><u>-</u></h3>
- Initial velocity,u = 23 m/s
- Acceleration,a = 1.8 m/s²
<h3><u>To</u><u> </u><u>be</u><u> </u><u>calculated:-</u><u> </u></h3>
Calculate the final velocity,v .
<h3><u>Solution:-</u><u> </u></h3>
As we know that,
Acceleration = v - u / t
⇒ 1.8 = v - 23 / 6.8
⇒ 1.8 × 6.8 = v - 23
⇒ 12.24 = v - 23
⇒ v = 12.24 + 23
⇒ v = 35.24 m/s
Thus,the final velocity of a car is 32.24 meters per seconds.
Precipitation in a cold front typically occurs around the outer edges of the cooler air mass. This is where the cool air meets the previously warm air.
Also, it can be said to happen at the front of the front and behind the front.