What happens when water at 4° celsius is heated further?
1 answer:
You might be interested in
We have that for the Question "A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that the minimum force that must be applied on the <em>book is</em>
- F=44N
From the question we are told
A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal
Generally the equation for the Force is mathematically given as
F=44N
Therefore
the minimum force that must be applied on the <em>book is</em>
F=44N
For more information on this visit
Answer:
E = 0 r <R₁
Explanation:
If we use Gauss's law
Ф = ∫ E. dA = / ε₀
in this case the charge is distributed throughout the spherical shell and as we are asked for the field for a radius smaller than the radius of the spherical shell, therefore, THERE ARE NO CHARGES INSIDE this surface.
Consequently by Gauss's law the electric field is ZERO
E = 0 r <R₁
Answer:
THE RUBBER BALL
Explanation:
From the question we are told that
The mass of the rubber ball is
The initial speed of the rubber ball is
The final speed at which it bounces bank
The mass of the clay ball is
The initial speed of the clay ball is
The final speed of the clay ball is
Generally Impulse is mathematically represented as
where is the change in the linear momentum so
For the rubber is
=>
For the clay ball
=>
So from the above calculation the ball with the a higher magnitude of impulse is the rubber ball