Answer:
If energy is conserved, then the sum of the potential energy and the kinetic energy is a constant.
Assuming the proton starts from rest, so it's kineitc energy is zero, but it has a potential energy, PE equal to:
PE = qV
where q =1.6 x 10^-19 C
and V = 1.00 V
Assuming the proton no longer experiences the potential energy and it is all converted to kinetic energy then:
PE* = 0,
KE* = 1/(2mv^2)
Now since
PE + KE = Total energy =PE* + KE*
Therefore,
qV + 0 = 0 + 1/2mv^2
Or
KE = qV = 1.6 10^-19 J
The change in momentum is 5500 kg m/s
Explanation:
The change in momentum of an object is given by

where
m is the mass of the object
v is the final velocity
u is the initial velocity
In this problem, we have:
(mass of the motorcycle)
(final velocity)
(initial velocity)
Therefore, the change in momentum is

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Answer:
magnitude of A − B = 15.81 km
Explanation:
Vector A points in the negative y-direction and has a magnitude of 5 km. Vector B points in the positive x-direction and has a magnitude of 15 km.
According to Cartesian coordinate system, the resultant will start either from tail of A and ends at head of B and vice-versa.
A(0,-5)
B(15,0)
A - B = (-15 i - 5 j )
Magnitude of the vector is given by
|A - B| = 
|A - B| = 
|A - B| = 15.81 km
The angle between 2 o'clock and 12 o'clock is referred to as the angle of twist. The angle between the planes of maximum shear which is bisected by the axis of greatest compression is angle of shear.
This question involves the concepts of equilibrium and Newton's third law of motion.
The support force will be "1 pound" for the empty bucket and the support force will be "6 pounds" after pouring water into it.
- According to the condition of equilibrium, the sum of forces acting on a stationary object must be zero. Hence, the support force of the table will be equal to the total mass of the bucket.
- According to Newton's Third Law of Motion every action force has an equal but opposite reaction force. Hence, the support force will be a reaction force to the weight of the bucket.
Therefore, the support force in each case will be equal to the total mass of the bucket:
Case 1 (empty bucket):
<u>support force = 1 pound</u>
<u></u>
Case 1 (water poured):
support force = 1 pound + 5 pound
<u>support force = 6 pound</u>
<u></u>
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