All categories

2 years ago

While fishing on a lake, a fisherman notices ripples 0.32 m apart, and they are

Physics

1 answer:

Karo-lina-s [1.5K]2 years ago

5 0

the main properties of the main wave propertioes include wavelength amplitude, cruest an trough

You might be interested in

One molecule of bromine (Br2) and two molecules of potassium chloride (KCI) combine in a reaction. How many atoms are in the pro

Liula [17]

In the reaction between 1 molecule of bromine and 2 molecules of potassium chloride, there are six atoms in the products.

Let's consider the balanced equation for the reaction between 1 molecule of bromine and 2 molecules of potassium chloride. This is a single replacement reaction.

Br₂ + 2 KCl ⇒ 2 KBr + Cl₂

We obtain as products, 2 molecules of potassium bromide and 1 molecule of chlorine.

1 molecule of KBr has 2 atoms, so 2 molecules contribute with 4 atoms.
1 molecule of Cl₂ has 2 atoms.
The 4 atoms from KBr and the 2 atoms from Cl₂ make a total of 6 atoms.

In the reaction between 1 molecule of bromine and 2 molecules of potassium chloride, there are six atoms in the products.

Learn more: brainly.com/question/21850455

5 0

3 years ago

Read 2 more answers

Find the final velocity of a 40 kg skateboarder traveling at an initial velocity of 10 m/s that moves up a hill from a height of

slavikrds [6]

Answer:

vf = 0

Explanation:

Since the initial height hi = 0, we can rewrite the energy equation as

vf^2 = vi^2 - 2ghf = (10 m/s)^2 - 2(10 m/s^2)(5 m) = 0

Therefore, his final velocity vf is

vf = 0

3 0

3 years ago

The resistance created by waves on a 120-m-long ship is tested in a channel using a model that is 4 m long Y Part A If the ship

DanielleElmas [232]

Answer:

$V_m = 12.78 km/hr$

Explanation:

given,

length of the ship = 120 m

length of model of the ship = 4 m

Speed at which the ship travels = 70 km/h

speed of model = ?

by using froude's law

$F_r = \dfrac{V}{\sqrt{L g}}$

for dynamic similarities

$(\dfrac{V}{\sqrt{L g}})_P = (\dfrac{V}{\sqrt{L g}})_{model}$

$(\dfrac{V_p}{\sqrt{L_p}}) = (\dfrac{V_m}{\sqrt{L_m}})$

$(\dfrac{70}{\sqrt{120}}) = (\dfrac{V_m}{\sqrt{4}})$

$V_m = 12.78 km/hr$

hence, the velocity of model will be 12.78 km/h

6 0

3 years ago

How many electrons can carbon accept from other atoms while bonding? (1 point)

solong [7]

Answer: Four electrons

Explanation:

7 0

3 years ago

Read 2 more answers

In a circus performance, a monkey on a sled is given an initial speed of 4.3 m/s up a 24◦ incline. The combined mass of the monk

Serggg [28]

Answer:

d = 1.15 m

Explanation:

In absence of friction, the change in kinetic energy of the combined mass of the monkey and the sled, must be equal (with opposite sign), to the change in gravitational potential energy:

ΔK = -ΔU

When friction is not negligible, the change in mechanical energy, must be equal to the work done by non-conservative forces (kinetic friction in this case):

ΔK + ΔU = Wnc (1)

As the monkey + sled reach to the maximum distance up the incline, they will come momentarily to a stop, so the final kinetic energy is 0.

$(K_{f} -K_{o}) = 0 - \frac{1}{2} * m*v_{o} ^{2} = -\frac{1}{2} *22.5kg*(4.3m/s)^{2} = -208.1J$

The change in gravitational energy, can be written as follows:

$(U_{f} - U_{o} ) = m*g*h - 0 = m*g*h = \\ \\ 22.5 kg*9.8 m/s2*d*sin (24 deg) = 89.7J*d$

The sum of these two quantities, must be equal to the work done by the friction force, along the distance d up the incline:

$W_{nc} = -\mu k*N*d$

The normal force, always normal to the surface, must be equal and opposite to the component of the weight normal to the incline:

$N = m*g*cos \theta = m*g*cos (24 deg) = \\ \\ 22.5 kg*9.8m/s2*0.913 = 201.4 N$

Replacing in the equation for Wnc:

$W_{nc} = -\mu k*N*d = -0.45*201.4 N*d = -90.6 N*d$

We can return to the equation (1) and solve for d:

$-208.1 J + 89.7N*d = -90.6N*d\\\\ d = \frac{208.1}{180.3} =1.15 m$

3 0

3 years ago