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Dima020 [189]
3 years ago
5

A 1.0 kilogram ball is thrown into the air with an initial velocity of 30m/s. How much kinetic energy does the ball have? (B) ho

w much potential energy does the ball have when it reaches the top of its accent? (C) how high into the air did the ball travel?
Physics
1 answer:
Gala2k [10]3 years ago
7 0

Answer:

450 joules ; 450 joules ; 45.9 m

Explanation:

Given that :

Initial Velocity, u = 30m/s

Mass, m = 1 kg

Kinetic Energy of ball (KE) = 0.5mu²

K. E = 0.5 * 1 * 30^2

K.E = 0.5 * 900

K.E = 450 Joules

B.) Potential Energy (P. E)

P. E = mgh

At the highest point, all kinetic energy has would have become potential energy, hence

K. E = P. E = 450 Joules

C) Height of the ball :

From ; P. E = mgh

Where ; g = acceleration due to gravity = 9.8m/s² ; h = height

450 = 1 * 9.8 * h

450 = 9.8h

h = 450 / 9.8

h = 45.918

h = 45.9 m

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Answer and Explanation:

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4 years ago
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a is the correct answer dear


3 0
3 years ago
A light-rail train going from one station to the next on a straight section of track accelerates from rest at 1.1 m/s2 for 20 s.
Kruka [31]
It accelerates from rest at 1.1 m/s^2 for 20s. 

<span>s = at^2/2 </span>
<span>s = (.5)(1.1)(20)^2= 220m </span>

<span>then it travels 1100m </span>

<span>Then it slows down at 2.2m/s^2 until it stops at the station. </span>

<span>Calculate the train's speed: </span>
<span>v = at </span>
<span>v = (1.1)(20) = 22m/s 
</span>
<span>Now, calculate the time to stop: </span>
<span>v = at </span>
<span>t = 22/2.2 = 10s </span>
<span>s = t(u+v)/2 </span>
<span>s = 10(0+22)/2 = 110m </span>

<span>(A) Total distance = 220 +1100+110 = 1430m </span>

<span>(B) Time = 20 + 1100/22 + 10 = 80s</span>
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