The control room is similar to the nucleus, because the nucleus is in charge of cell functions.
Answer:
D) 0 k.cal per 4 grams
Explanation:
Genarally, glucose can be classified into two enantiomers such as d-glucose and l-glucose. The d-glucose is the most common sugar that bodies of living organisms use as source of energy. However, l-glucose is an organic compound and it is one of the aldohexose monosaccharides. It is the l-isomer of glucose and commonly refer to as a low-calorie sweetener. The l-glucose is relatively indistinguishable in taste from d-glucose but cannot be used as a source of energy. Therefore, in the given problem:
if d-glucose has an estimated caloric value of 1 k.cal per 4 grams of carbohydrate, then the caloric value of l-glucose will be 0 k.cal per 4 grams.
I am sure it is DNA polymerase.
I'm a bio major, hope I helped :)
