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balandron [24]
3 years ago
7

What is a dependent or responding variable? Can someone help me?

Physics
1 answer:
Svetllana [295]3 years ago
8 0

They are a variable that changes as a result of the changes in the manipulated variable

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Two blocks of clay, one of mass 1.00 kg and one of mass 7.00 kg, undergo a completely inelastic collision. Before the collision
RideAnS [48]

Answer:8 m/s

Explanation:

Given

m_1=1 kg

m_2=7 kg

kinetic Energy of m_1=32 J

initially m_2 is at rest and let say m_1 is moving with velocity u

kinetic Energy of m_1 is =\frac{m_1u^2}{2}=32

u^2=64

u=8 m/s

In Completely inelastic collision both mass stick together and move with common velocity

Suppose v is the common velocity

m_1u+0=(m_1+m_2)v

v=\frac{1\times 8}{1+7}=1 m/s

therefore Final velocity with which both blocks moves is 1 m/s

7 0
3 years ago
You have been asked to recommend a alternative source of energy that your town could use to generate electricity. Describe the r
snow_tiger [21]
I believe that solar energy would be the best energy for my town.  Solar energy is advantageous because the sun is up every day, and because it takes up much less space than than some other sources of renewable energy.  Some disadvantages of solar energy are that if there is cloud cover, hardly any energy will be gained at all.  Another disadvantage is that it is a long term investment that can take a while for it to pay for itself.
3 0
3 years ago
To become positively charged an átom must
Ivanshal [37]

Lose electrons because they have a negative charge.

7 0
3 years ago
Read 2 more answers
A helicopter starting on the ground is rising directly into the air at a rate of 25 ft/s. You are running on the ground starting
rusak2 [61]

Answer:

The rate of change of the distance between the helicopter and yourself (in ft/s) after 5 s is \sqrt{725} ft/ sec

Explanation:

Given:

h(t) =  25 ft/sec

x(t) = 10 ft/ sec

h(5) = 25 ft/sec . 5 = 125 ft

x(5) = 10 ft/sec . 5 = 50 ft

Now we can calculate the distance between the person and the helicopter by using the Pythagorean theorem

D(t) = \sqrt{h^2 + x^2}

Lets find the derivative of distance with respect to time

\frac{dD}{dt} (t)  = \frac{2h \cdot \frac{dh}{dt} +2x \cdot\frac{dx}{dt}} {2\sqrt{h^2 + x^2}}

Substituting the values of h(t) and  x(t) and simplifying we get,

\frac{dD}{dt}(t) = \frac{50t \cdot \frac{dh}{dt} + 20 \cdot \frac{dx}dt}{2\sqrt{625\cdot t^2 + 100 \cdot t^2}}

\frac{dh}{dt} = 25ft/sec

\frac{dx}{dt} = 10 ft/sec

\frac{Dd}{dt} (t) = \frac{1250t +200t}{2\sqrt{725}t}  = \frac{725}{\sqrt{725}}  = \sqrt{725} ft / sec

5 0
3 years ago
Pooping in my room and my room is upstairs and upstairs bathroom upstairs
diamong [38]

Answer:

huh? do you need help on math?

Explanation:

what do you mean?

7 0
2 years ago
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