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balandron [24]
3 years ago
7

What is a dependent or responding variable? Can someone help me?

Physics
1 answer:
Svetllana [295]3 years ago
8 0

They are a variable that changes as a result of the changes in the manipulated variable

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1.A graduated cylinder with a least count of = 0.5 ml is used in a density
Anna007 [38]

We have that

 

From the question we are told

  • A graduated cylinder with a least count of \pm 0.5 ml
  • The initial water level, before inserting the irregular
  • shaped solid.
  • Is 30.0 ml. After inserting the solid,
  • The water level is 34.5 ml.

Generally the equation for the new quantity. is mathematically given as

X=Initial level - Final Level \pm (initial and final error)

Therefore

X (34.5-30.0) \pm(0.5+0.5)\\\\X= 4.5\pm 1.0

Therefore

The Probable error is

x=\pm 1.0ml

For more information on this visit

brainly.com/question/23366835?referrer=searchResults

4 0
3 years ago
what is the wavelength of light (in nanometers) that has a frequency of 1.75 x 1013 hz? the speed of light is 3.00 x 108 m/s.
Leokris [45]

The light has a frequency of 1.75 x 10¹³ hz. The speed of light is 3.00 x 10⁸ m/s. The wavelength of light is (λ) = 1.714 x 10⁴ nm

<h3>What is wavelength?</h3>

When a wave that propagates in a medium it has different lengths. That length of the wave is called the wavelength. It can be measured in m, cm, nm etc.

<h3>How can we calculate the wavelength?</h3>

To calculate the wavelength we are using the formula,

λ=c/f

Here we are given,

c= The speed of light in zero space. = 3.00 x 10⁸ m/s.

f = The frequency of the light. = 1.75 x 10¹³ hz.

We have to calculate the wavelength of the light = λ m

Now we put the values in above equation we get,

λ=c/f

Or, λ=3.00 x 10⁸ / 1.75 x 10¹³

Or,  λ= 1.714 x 10⁻⁵ m

So we can easily say that,

The wavelength of light is (λ) =1.714 x 10⁻⁵ m = 1.714 x 10⁴ nm

Learn more about wavelength:

brainly.com/question/10728818

#SPJ4

5 0
1 year ago
What would a wave with a low amplitude sound like?.
tresset_1 [31]

If you could hear it at all, it would sound very soft.

6 0
3 years ago
calculate the kinetic energy of a car with a mass of 500kg traveling at a velocity of 10m/s^2 north. A) 2,500j B) 25,000j C) 50,
Arte-miy333 [17]
The correct answer would be A) 2,500j
8 0
3 years ago
The x-coordinates of two objects moving along the x-axis are given as a function of time (t). x1= (4m/s)t x2= -(161m) + (48m/s)t
Kitty [74]
The two displacement functions are
x₁ = 4t
x₂ = -161 + 48t - 4t²
where
x₁, x₂ are in meters
t is time, s

The distance between the two objects is
x = x₁ - x₂
   =  4t + 161 - 48t + 4t²
x = 4t² - 44t + 161

Write this equation in the standard form for a parabola.
x = 4[t² - 11t] + 161
  = 4[ (t - 5.5)² - 5.5² ] + 161
 x = 4(t-5)² + 40

Ths is a parabola that faces up and has its vertex (lowest point) at (5, 40).
Therefore the closest approach of the two objects is 40 m.
The graph of x versus t confirms the result.

Answer: The distance of the closest approach is 40 m.

5 0
3 years ago
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