Answer:
A low difference in the concentration of the molecule across the media
Explanation:
Diffusion is a type of passive transport where the molecules move in the influence of concentration gradient of diffusing molecules i.e. from the higher concentration region to the lower concentration region. There are some factors which affect the rate of diffusion, these are written below -
- Mass of diffusing molecule - lighter molecules diffuse faster and heavier one diffuse relatively slower.
- Concentration gradient - rate of diffusion is higher if the difference in concentration of the diffusing particles is larger in the two regions.
- Distance traveled - molecules diffuse faster if they need to travel little distance during diffusion.
- Temperature - rate of diffusion will be greater at higher temperatures because the movement of diffusing molecules gets increased.
- Solvent density - rate of diffusion tend to be lower if the solvent has higher density.
Looking at these factors we can conclude that the second statement in the question tells about a negative impact regarding the diffusion because due to low difference in concentration across the two media, the rate of diffusion will be lower.
Answer:
4. 10.0 m/s²
Explanation:
I) if initial velocity is 'v₀', the final velocity is 'v', the accelaration is 'a', the distance is 'L' and elapsed time if 't', then:


II) using these two equations after substitution v₀=0; v=30 and L=45:


Happy Holidays!
Recall that:
Impulse = Change in Momentum = mass × change in velocity
Since both cars are identical and have the same initial velocity of 60 mph, them breaking to a stop means that they both experience the same change in velocity.
Thus, both of the cars' impulses are equal.
Answer:
Maybe because you not throwing it stringer or lighter. And you need to control yourself prob. maybe you did line it correctly or maybe your just bad to be honest. -.-
Explanation: