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svetoff [14.1K]
3 years ago
10

if a car is accelerating downhill under a net force of 3674 N, what additional force would cause the car to have a constant velo

city?
Physics
1 answer:
expeople1 [14]3 years ago
3 0

Hi there!

For an object to have a constant velocity, the SUM of the forces must equal 0. This means that the forces are balanced.

When a car is accelerating downhill, it is experiencing a force due to gravity of F = MgsinФ.

In order to balance the forces, there must be an equal and OPPOSITE force acting on the object. This would be a force of kinetic friction.

Thus:

∑F = -F (Kinetic Friction) + MgsinФ

0 = -F (Kinetic Friction) + MgsinФ

MgsinФ = F (Kinetic Friction)

Thus, the force of Kinetic Friction = -3674 N

(Negative indicates in the opposite direction)

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Brayden and Riku now use their skills to work a problem. Find the equivalent resistance, the current supplied by the battery and
Liono4ka [1.6K]

a) 5 \Omega, 1.6 A

b) 6 \Omega, 1.33 A

Explanation:

a)

In this situation, we have two resistors connected in series.

The equivalent resistance of resistors in series is equal to the sum of the individual resistances, so in this circuit:

R=R_1+R_2

where

R_1=4\Omega

R_2=1 \Omega

Therefore, the equivalent resistance is

R=4+1=5 \Omega

Now we can use Ohm's Law to find the current flowing through the circuit:

I=\frac{V}{R}

where

V = 8 V is the voltage supplied by the battery

R=5\Omega is the equivalent resistance of the circuit

Substituting,

I=\frac{8}{5}=1.6 A

The two resistors are connected in series, therefore the current flowing through each resistor is the same, 1.6 A.

b)

In this part, a third resistor is added in series to the circuit; so the new equivalent resistance of the circuit is

R=R_1+R_2+R_3

where:

R_1=4\Omega\\R_2=1\Omega\\R_3=1\Omega

Substituting, we find the equivalent resistance:

R=4+1+1=6 \Omega

Now we can find the current through the circuit by using again Ohm's Law:

I=\frac{V}{R}

where

V = 8 V is the voltage supplied by the battery

R=6\Omega is the equivalent resistance

Substituting,

I=\frac{8}{6}=1.33 A

And the three resistors are connected in series, therefore the current flowing through each resistor is the same, 1.33 A.

3 0
3 years ago
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