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3 years ago

What is the product? (-2087+5) (50²-6s)

Mathematics

1 answer:

gayaneshka [121]3 years ago

3 0

Answer:

-5092500+12222s

Step-by-step explanation:

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10. For the equation 3x – 4 = 8, which

irga5000 [103]

Answer:

x = 4

Step-by-step explanation:

We can find the answer to this by solving the equation:

3x - 4 = 8

3x - 4 + 4 = 8 + 4

3x = 12

x = 4

6 0

3 years ago

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a cookie jar contains four oatmeal raisin, one sugar, nine chocolate chip, and six peanut butter cookies. if one is chosen at ra

VikaD [51]

Step-by-step explanation:

There are a total of 4 + 1 + 9 + 6 = 20 cookies. So the probabilities of each type for a random cookie are:

P(oatmeal raisin) = 4/20 = 1/5

P(sugar) = 1/20

P(chocolate chip) = 9/20

P(peanut butter) = 6/20 = 3/10

8 0

3 years ago

This table on a package of dog food tells how much to feed a dog, depending on its weight. Weight of Dog (pounds)153045 Amount

Novay_Z [31]

9514 1404 393

Answer:

k = 2/15

Step-by-step explanation:

We can solve the given equation for k:

k = s/p . . . . . . divide the given equation by p on both sides

Using the first values from the table (15 pounds, 2 scoops), we have ...

k = 2/15

The value of k is 2/15.

3 0

3 years ago

Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g

SpyIntel [72]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see $\bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad B
\end{array}$

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.

8 0

3 years ago

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Will mark as brainliest!!!!!!!!!!

statuscvo [17]

Answer:

hi I just wanna talk ;)

Step-by-step explanation:

4 0

3 years ago