2H2+O2→2H2O
We have to be aware that the number of atoms are the same on both reactant side and product side.
Explanation:
2H2O2 => 2H2O + O2
Moles of hydrogen peroxide = 0.150dm³ * (0.02mol/dm³) = 0.003mol .
Moles of oxygen = 0.0015mol.
Volume of oxygen = 0.0015mol * (22.4dm³/mol) = 0.0336dm³.
Answer:
The electrons in an atom move around the nucleus in regions known as electron shells.
Answer:
8.75 g of ZnO
Solution:
The Balance Chemical Reaction is as follow,
2 ZnS + 3 O₂ → 2 ZnO + 2 SO₂
Step 1: Find out the limiting reagent as;
According to Equation ,
194.94 g (2 mole) ZnS reacts with = 96 g (3 moles) of O₂
So,
12.85 g of ZnS will react with = X g of O₂
Solving for X,
X = (12.85 g × 96 g) ÷ 194.94 g
X = 6.32 g of O₂
It means for total utilization of 12.85 g of ZnS we require 6.32 g of O₂, but we are provided with 15.91 g of O₂. Therefore, ZnS is the limiting reagent and will control the yield.
Step 2: Calculate Amount of ZnO produced as;
According to Equation ,
194.94 g (2 mole) ZnS produces = 132.81 g (2 moles) of ZnO
So,
12.85 g of ZnS will produce = X g of ZnO
Solving for X,
X = (12.85 g × 132.81 g) ÷ 194.94 g
X = 8.75 g of ZnO
<span>some elements would be Beryllium, Barium, Magnesium, and Strontium</span>
