Molar mass of Li = 6.9 g/mol
6.9 g -------------------- 6.0x10²³ atoms
g -------------------- 2.75x10^21 atoms
6.0x10²³ g = 6.9 * (2.75x10^21)
6.0x10²³ g = 1.8975x10²²
g = 1.8975x10²² / 6.0x10²³
x = 0,0317 g
answer b
hope this helps!.
Resistivity is a measure of the resistance of a given size of a specific material to electrical conduction. ... Materials that conduct electrical current easily are called conductors and have a low resistivity. Those that do not conduct electricity easily are called insulators and these materials have a high resistivity.
Acidosis is a disorder in which there is excess acid in the body. This condition can lead to hyperkalemia due to the diffusion of hydrogen ions in the intracellular fluid.
<h3>What is hyperkalemia?</h3>
Hyperkalemia is an increased concentration of the fluid potassium level than normal. Though potassium (K) is needed by the body for various functions of the nervous system and muscles their excess can lead to diseases.
It can also be caused by acidosis, where the concentration of the hydrogen ion increases in the intracellular fluid which leads to a large movement of potassium ions toward the extracellular fluid.
Therefore, the condition of acidosis can cause <u>hyperkalemia</u>.
Learn more about hyperkalemia here:
brainly.com/question/8920601
#SPJ4
The reactivity and other chemical properties of an organic molecule are primarily dependent upon <span>the attached functional group </span>of the molecule.
For example hydroxyl group (-OH) in alcohols or carboxyl group in c<span>arboxylic acid are poplar groups and that is why this compounds are polar.</span>
The atoms of functional groups are linked to each other and to the rest of the molecule with covalent bonds.
Answer:The structures of 3-brominated products are available in attachment. Kindly find in attachment.
Explanation:
1-ethyl-4-methylbenzene undergoes a radical substitution reaction when it is treated with NBS(N-bromosuccinimide).
There are 3 products which are produced in the reaction.
There are 2 positions available where bromination can occur one at 1 position and other at 4 position.
There is a ethyl group present at 1-position and a methyl group is present at 4-position.
At the 1-position where ethyl group is present 1-phenylethyl radical is generated on irradiation with UV-light. Now since this 1-phenylethyl radical is planar and a chiral centre as all groups attached to the carbon center is different hence two products of bromination can occur from this position. One from below the plane and other from above the plane. These 2 products can form with equal probability.
In one product the Bromine radical can combine with 1-phenylethyl radical form above the plane and in other product bromine radical can combine with 1-phenyl radical form below the plane.
Hence 1-phenylethyl radical would lead to products which would be 2 stereiosomers and would be known as enantiomers (mirror images).
Radical generated at 4 position that is at methyl position would be a benzyl radical and this would also be planar but since it is not a chiral center hence both the sides would be equivalent so only one product would be generated.
Kindly find in attachment for the structures of the products and reactants.