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pashok25 [27]
4 years ago
5

Candle flames are actually what shape??​

Chemistry
2 answers:
navik [9.2K]4 years ago
6 0

Answer:

teardrop

Explanation:

Ket [755]4 years ago
3 0

Answer:

Actually the shape should be that of a sphere, because light and heat is radiated outwards, but because of heat, the air becomes light and less denser, due to which it rises up, and hence we get that shape.

Explanation:

Hope this helps :), never atcually thought about that lol

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Identify the NMR term that corresponds to each description.
balandron [24]

Answer:

A- upfield

B- down field

C- splitting

D- chemical shift

E- integration

Explanation:

NMR is a spectroscopic technique commonly used to observe the magnetic fields around the nucleus of atoms in a compound under investigation.

A chemical shift is the difference in parts per million (ppm) between the resonance frequency of the observed protons in the compound under study and that of the tetramethylsilane (TMS) (the reference compound in NMR with a chemical shift of zero ppm because all protons in the compound are equivalent).

If signals appear close to the reference signal, the signals are said to appear upfield. If the signals appear far away from the reference, they are said to appear down field.

The presence of protons cause splitting of peaks to the magnitude of n+1. n is the number of neighboring protons. Splitting refers to the appearance of multiple peaks for a single nucleus due to neighboring nuclei.

The area of a signal that corresponds to the number of nuclei at that frequency is called the integration.

4 0
3 years ago
How does thermal energy travel?
Softa [21]
Thermal energy travels<span> by conduction, convection, and radiation. It occurs when a cooler and warmer object touches each other. </span>
7 0
3 years ago
Read 2 more answers
The half-life of nitrogen-13 is 10.0 minutes. if you begin with 53.3 mg of this isotope, what mass remains after 25.9 minutes ha
zimovet [89]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

P (Half-life) = 10.0 minutes

T (Elapsed time for sample reduction) = 25.9 minutes

Let's find the number of periods elapsed (x), let us see:

T = x*P

25.9 = x*10.0

25.9 = 10.0\:x

10.0\:x = 25.9

x = \dfrac{25.9}{10.0}

\boxed{x = 2.59}

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

m =  \dfrac{m_o}{2^x}

m =  \dfrac{53.3}{2^{2.59}}

m \approx \dfrac{53.3}{6.021}

\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

3 0
3 years ago
A bomb calorimetric experiment was run to determine the enthalpy of combustion of ethanol. The reaction is The bomb had a heat c
gulaghasi [49]

Answer:

The enthalpy of combustion of ethanol in kJ/mol is -1419.58  kJ/mol.

Explanation:

The heat absorbed by the bomb and water is equal to the product of the heat  capacity and the temperature change. Working with this equation, and assuming no heat is lost to  the surroundings, we write :

qcal= Ccal × ΔT= 490 J/K × 276.7 K= <u>135,583 J</u> = 135.58 kJ

Note we expressed the temperature change in K, because the heat capacity is written in K.

<u> Now that we have the heat of combustion, we need to calculate the molar heat.  </u>

Because qsystem = qrxn + qcal and qrxn = -qcal, the heat change of the reaction is -135.58 kJ.

This is the heat released by the combustion of 4.40 g of ethanol ; therefore, we can write  the <u>conversion factor as 135.58 kJ/ 4.40 g</u>.

The molar mass of ethanol is 46.07 g, so the heat of combustion of 1 mole of ethanol is :

molar heat of combustion= -135.58 kJ/4.40 g x 46.07 g/ 1 mol= -1419.58 kJ/mol

Therefore, the enthalpy of combustion of ethanol in kJ/mol is -1419.58  kJ/mol.

3 0
4 years ago
Mass , volume, and density are all properties of what
Vladimir [108]

Answer: Physical properties

Explanation: Can be measured without changing a substance's chemical identity.

4 0
3 years ago
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