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pashok25 [27]
3 years ago
5

Candle flames are actually what shape??​

Chemistry
2 answers:
navik [9.2K]3 years ago
6 0

Answer:

teardrop

Explanation:

Ket [755]3 years ago
3 0

Answer:

Actually the shape should be that of a sphere, because light and heat is radiated outwards, but because of heat, the air becomes light and less denser, due to which it rises up, and hence we get that shape.

Explanation:

Hope this helps :), never atcually thought about that lol

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How many atoms of chlorine (Cl) are shown below? <br><br> 5 CaCl2
Jobisdone [24]
The answer is not C...
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An empty plastic bottle is sealed in a cool room and then moved to a very hot room. What can best be stated about the air pressu
andriy [413]
<span>It is higher than the pressure on the outside of the bottle.</span>
3 0
3 years ago
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Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. The energy of one photon of this
Sedbober [7]

<u>Answer:</u> The energy of one photon of the given light is 3.79\times 10^{-19}J

<u>Explanation:</u>

To calculate the energy of one photon, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

\lambda = wavelength of light = 525nm=5.25\times 10^{-7}m        (Conversion factor:  1m=10^9nm  )

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

Putting values in above equation, we get:

E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{5.25\times 10^{-7}mm}\\\\E=3.79\times 10^{-19}J

Hence, the energy of one photon of the given light is 3.79\times 10^{-19}J

3 0
2 years ago
The two balanced equations (1) and (2) are for reactions in which gaseous carbon dioxide is produced from the combustion of (1)
V125BC [204]

Answer:

2.0 mol of oxygen are consumed.

Step-by-step explanation:

You know that you will need a balanced equation with masses, moles, and molar masses, so gather all the information in one place.

M_r:   28.0                 44.0

          CO  + ½O₂ ⟶ CO₂ + 67.6 kcal

m/g:   112

<em>Step 1</em>. Convert grams of CO to moles of CO

1 mol CO = 28.0 g CO

Moles of CO = 112 × 1/28.0

<em>Step 2.</em> Convert moles of CO to moles of CO₂.

The molar ratio is 1 mol CO₂ to 1 mol CO

Moles of CO₂ = 4.000 × 1/1

Moles of CO₂ = 4.00 mol CO₂

Option A is <em>wrong</em>.

<em>Step 3.</em> Calculate the amount of heat generated.

q = ΔH

The conversion factor is 67.6 kcal/1 mol CO₂

q = 4.00 × 67.6

q = 270 kJ

Option B is <em>wrong</em>, because it gives the heat generated by 1 mol of CO.

<em>Step 4. </em>Calculate the moles of O₂ consumed

Moles of O₂ = 2.00 mol O₂

Option C is correct.

<em>Step 5.</em> Calculate the moles of CO₂ formed

Already done in Step 2.

Moles of CO₂ = 4.00 mol CO₂

Option D is <em>wrong. </em>

<em> </em>

<em>Step 6</em>. Calculate the moles of O₂ produced

Already done in Step 4.

Moles of O₂ = 2.00 mol O₂

Option E is <em>wrong. </em>

3 0
3 years ago
what is the molarity of a solution prepared dissolving 317 g of CaCl2 into enough water to make 2.50 L of solution?
Minchanka [31]

Answer:

1.14 M

Explanation:

Step 1: Calculate the moles corresponding to 317 g of calcium chloride (solute)

The molar mass of calcium chloride is 110.98 g/mol.

317 g CaCl₂ × 1 mol CaCl₂/110.98 g CaCl₂ = 2.86 mol CaCl₂

Step 2: Calculate the molarity of the solution

Molarity is equal to the moles of solute divided by the liters of solution.

M = moles of solute / liters of solution

M = 2.86 mol / 2.50 L = 1.14 mol/L = 1.14 M

4 0
2 years ago
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