The mass of nucleons (and thus of the nucleus) is roughly 1000 times greater than that of electrons.
2.1648 kg of CH4 will generate 119341 KJ of energy.
Explanation:
Write down the values given in the question
CH4(g) +2 O2 → CO2(g) +2 H20 (g)
ΔH1 = - 802 kJ
2 H2O(g)→2 H2O(I)
ΔH2= -88 kJ
The overall chemical reaction is
CH4 (g)+2 O2(g)→CO2(g)+2 H2O (I) ΔH2= -890 kJ
CH4 +2 O2 → CO2 +2 H20
(1mol)+(2mol)→(1mol+2mol)
Methane (CH4) = 16 gm/mol
oxygen (O2) =32 gm/mol
Here 1 mol CH4 ang 2mol of O2 gives 1mol of CO2 and 2 mol of 2 H2O
which generate 882 KJ /mol
Therefore to produce 119341 KJ of energy
119341/882 = 135.3 mol
to produce 119341 KJ of energy, 135.3 mol of CH4 and 270.6 mol of O2 will require
=135.3 *16
=2164.8 gm
=2.1648 kg of CH4
2.1648 kg of CH4 will generate 119341 KJ of energy
The correct answer is D. Using the law of conservation of mass the number of atoms on each side of the equation should be equal. Through introspection, we find that there are 2
atoms on reactant side as opposed 3Cl atoms on product side. If we add a coefficient of 3 on 
we get
.
Now there are 6Cl atoms on reactant side and 2 on product side, hence we add a coefficient of 2 on both 
and 
. The balanced chemical equation is,
<h3>
Answer:</h3>
6AgI + Fe₂(CO₃)3 → 2FeI₃+ 3Ag₂CO₃
<h3>
Explanation:</h3>
- The process of balancing chemical equations involves putting coefficients on reactants and products to ensure the number of atoms of each element is equal on both sides of the equation.
- It is a try and error method that is done to make an equation obey the law of conservation of mass.
In this case;
- Our unbalanced equation is, AgI + Fe₂(CO₃)3 → FeI₃+ Ag₂CO₃
- It can be balanced by putting the coefficients 6, 1, 2, 3.
- Therefore, the balanced chemical equation is;
6AgI + Fe₂(CO₃)3 → 2FeI₃+ 3Ag₂CO₃
