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Amanda [17]
3 years ago
15

17) How many grams are in 0.02 moles of beryllium iodide, Bel2?

Chemistry
2 answers:
Andreas93 [3]3 years ago
8 0

Answer: 5.26 g BeI2

Explanation: For 1 mole of BeI2 it is to its molar mass

Be mass is 9 and I mass is 127 x 2

The molar mass is 263 g BeI2

Solution:

0.02 moles BeI2 x 263 g BeI2/ 1 mole BeI2

= 5.26 g BeI2

Alinara [238K]3 years ago
5 0

Answer:

beryllium iodide has a molar mass of 262.821 g mol−1 , which means that 1 mole of beryllium iodide has a mass of 262.821 g . To find the mass of 0.02 moles of beryllium iodide, simply multiply the number of moles by the molar mass in conversion factor form.

Explanation:

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Answer : Option 4) Region of the most probable electron location.


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This electron cloud model was different from the older Bohr atomic model by Niels Bohr.

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Saponification is a chemical reaction _____. A. due to the presence of a strong organic acid. B. that results in an alcohol and
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Answer:

that results in an alcohol and a carboxylic acid.

Explanation:

Saponification is a chemical reaction process of alkaline hydrolysis of esters(R'COOR group) by which soap is obtained.

For Example, when a base such as sodium hydroxide [NaOH]  is used to hydrolyze an ester, the products are a carboxylate salt and an alcohol. Because soaps are prepared by the alkaline hydrolysis of fats and oils.

In a saponification reaction, alkaline hydrolysis of fats and oils with sodium hydroxide  yields propane-1,2,3-triol and the corresponding sodium salts of the component fatty acids.

i.e  Fat or oil + caustic alkali ⇒ Soap + propane-1,2,3-triol

As a specific example, ethyl acetate and NaOH react to form sodium acetate and ethanol:

The reaction goes to completion in the image below:

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3 years ago
Which is a column running up and down in the periodic table?
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2 years ago
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In the hydrologic cycle, water from the ocean into the atmosphere where it can and change back into tiny water droplets.
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2 years ago
Two reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.79 2 C − ⇀ ↽ − D K 2 = 0.186 Calculate the
vfiekz [6]

Answer:

K=1.93

Explanation:

Given reactions are:

A +2B ⇄ 2C  K1=2.79

2C ⇄ D K2=0.186

D⇄ A+ 2B K=?

If we reverse the reaction then the euillibrium constant also become reciprocal of original value:

3rd reaction is a combination of reciprocal of 1st and 2nd reaction

2C⇄A +2B   1/K1;........................1

D ⇄ 2C  1/K2; ..............................2

On adding 1 and 2

D ⇄A +2B    K=\frac{1}{K1} \times\frac{1}{K2};

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