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Nataliya [291]
3 years ago
15

The group number for alkali metals

Chemistry
1 answer:
kirill115 [55]3 years ago
6 0

The alkali metals include: lithium, sodium, potassium, rubidium, cesium, and francium.

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I need help with my homework.Calculate the number of formula units in: 41.5 grams CaBr2
lana66690 [7]

Answer:

\text{ }1.25\times10^{23}\text{ formula units}

Explanation:

Here, we want to calculate the number of formula units in the given molecule

We start by getting the number of moles

To get the number of moles, we have to divide the mass given by the molar mass

The molar mass is the mass per mole

The molar mass of calcium bromide is 200 g/mol

Thus, we have the number of moles as follows:

\frac{41.5}{200}\text{ = 0.2075 mol}

The number of formula units in a mole is:

1\text{ mole = 6.02 }\times10^{22}\text{ formula units}

The number of formula units in 0.2075 mole will be:

0.2075\text{ }\times6.02\times10^{23}\text{ = }1.25\times10^{23}\text{ formula units}

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3 years ago
What ion the element P forms? Explain.
emmasim [6.3K]
Phosphorus is in group 15 meaning it have 5 valence electrons. This means that it needs 3 more electrons to create a full outer shell. As these three electrons are negatively charged it means that P is a 3- ion (it’s an anion [negatively charged ion])
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How many moles are there in 1.09 kg of Al(OH)3?
alina1380 [7]
  question   1
moles  =  mass/molar  mass  of  Al(OH)3
convert   Kg  to  g
that  is  1.09  x  1000=1090g

moles  is  therefore=1090g/78(molar  mass  of Al(OH)3)=  13.974 moles

   question  2
moles=
2.55g/327.2(molar   mass  of  Pb(CO3)2=  7.79  x   10^-3   moles
from  avogadro  constant
1moles=6.02  x10^23  formula  units
what  about  7.79  x  10  ^-3
={(7.79  x  10^-3)moles  x ( 6.02  x10^23)} /1  mole=4.69  x10^21  formula  units
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3 years ago
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