Answer:
<em>heterogeneous mixture is a mixture that is non-uniform and contains smaller component parts.</em>
60+68=128
128/2=64
so the answer is 64
I hope this helped
The number of protons tells you which element the atom is. The number of protons is the element number (Hydrogen - 1, Helium - 2, etc.).
Answer:
Molecular formula of cyanogen is C₂N₂
Explanation:
We apply the ideal gases law to find out the mole of cyanogen
P . V = n. R. T
Firstly let's convert the pressure in atm, for R
750 mmHg = 0.986 atm
25°C + 273 = 298K
0.986 atm . 0.714L = n . 0.082 L.atm/mol.K .298K
(0.986 atm . 0.714L) / (0.082 L.atm/mol.K .298K) = n
0.0288 mol = n
Molar mass of cyanogen = mass / mol
1.50 g /0.0288 mol = 52.02 g/m
Let's apply the percent, to know the quantity of atoms
100 g of compound contain 46.2 g of C and 53.8 g of N
52.02 g of compound contain:
(52.02 . 46.2) / 100 = 24 g → 2 atoms of C
(52.02 . 53.8) / 100 = .28 g → 2 atoms of N
Answer:
NO will be the limiting reagent.
Explanation:
The balanced equation is:
2 NO + 2 CO → N₂ + 2 CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- NO: 2 moles
- CO: 2 moles
- N₂: 1 mole
- CO₂: 2 moles
Being the molar mass of each compound:
- NO: 30 g/mole
- CO: 28 g/mole
- N₂: 28 g/mole
- CO₂: 44 g/mole
Then by stoichiometry the following quantities of mass participate in each reaction:
- NO: 2 moles* 30 g/mole= 60 g
- CO: 2 moles* 28 g/mole= 56 g
- N₂: 1 mole* 28 g/mole= 28 g
- CO₂: 2 moles* 44 g/mole= 88 g
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
To determine the limiting reagent, you can use a simple rule of three as follows: If 56 grams of CO react with 60 grams of NO, 3 grams of CO react with how much mass of NO?

mass of NO= 3.21 grams
But 3.21 grams of NO are not available, 3 grams are available. Since you have less moles than you need to react with 3 grams of CO, <u><em>NO will be the limiting reagent.
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