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Aneli [31]
3 years ago
10

A ball thrown in to the air starts out with an initial upward velocity but eventually slows and stops before falling back to the

ground. Which of the following contributes the most to the change in the motion of the ball?Question 2 options: a) The initial force with which the ball was thrown b) The downward force of gravity c) The resistance against the atmosphere d) The increase of inertia.
Physics
1 answer:
Mashutka [201]3 years ago
8 0

Answer:

b) The downward force of gravity

Explanation:

The gravity force has the biggest influence on the deceleration of the ball because no matter how much force you applied on the ball, it will eventually go down again, according to newton's second law:

\sum F=m.a

right after you throw the ball, only the force exerted by the gravity will affect the ball (neglecting air resistance):

m.g=m.a\\a=g

so the object will eventually be going down again.

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011 10.0 points
Ulleksa [173]

Answer:

2.47 m

Explanation:

Let's calculate first the time it takes for the ball to cover the horizontal distance that separates the starting point from the crossbar of d = 52 m.

The horizontal velocity of the ball is constant:

v_x = v cos \theta = (25)(cos 35.9^{\circ})=20.3 m/s

and the time taken to cover the horizontal distance d is

t=\frac{d}{v_x}=\frac{52}{20.3}=2.56 s

So this is the time the ball takes to reach the horizontal position of the crossbar.

The vertical position of the ball at time t is given by

y=u_y t - \frac{1}{2}gt^2

where

u_y = v sin \theta =(25)(sin 35.9^{\circ})=14.7 m/s is the initial vertical velocity

g = 9.8 m/s^2 is the acceleration of gravity

And substituting t = 2.56 s, we find the vertical position of the ball when it is above the crossbar:

y=(14.7)(2.56) - \frac{1}{2}(9.8)(2.56)^2=5.52 m

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above the crossbar.

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3 years ago
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