The formula for this problem that we will be using is:
F * cos α = m * g * μs where:F = 800m = 87g = 9.8
cos α = m*g*μs/F= 87*9.8*0.55/800= 0.59 So solving the alpha, find the arccos above.
α = arccos 0.59 = 54 ° is the largest value of alpha
Answer:
15.106 N
Explanation:
From the given information,
The weight of the bucket can be calculated as:

The mass of the water accumulated in the bucket after 3.20s is:


To determine the weight of the water accumulated in the bucket, we have:



For the speed of the water before hitting the bucket; we have:


v = 8.4 m/s
Now, the force required to stop the water later when it already hit the bucket is:


F = 1.68 N
Finally, the reading scale is:
= 7.154 N + 6.272 N + 1.68 N
= 15.106 N
Answer:
0.0605 Kg m^2
Explanation:
In this case where we have find he moment of inertia of this object about an axis perpendicular to the x-y plane and passing through the origin, we can just add three moment of inertia's .
MOI= 0.25×0.3^2 + 0.35×0.4^2- 0.45×0.2^2
= 0.0605 Kg m^2