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SpyIntel [72]
3 years ago
10

The ATP synthase complex allows ATP production by A. proton-driven rotation of the Fo subunit, which causes F1 to change conform

ation due to that rotation, allowing ADP to be phosphorylated to ATP. B. substrate-level phosophorylation. C. generating the adenosine to produce ATP. D. pumping electrons across the membrane at the end of an ETS
Physics
1 answer:
zloy xaker [14]3 years ago
3 0

Answer:

A. proton-driven rotation of the Fo subunit, which causes F1 to change conformation due to that rotation, allowing ADP to be phosphorylated to ATP

Explanation:

To answer the question we need to understand the following.

What is ATP synthase?

  • ATP synthase is an enzyme that is found in the electron transport chain which is the final phase of cellular respiration.

What is the Role of ATP synthase?

  • The role of ATP synthase is to synthesize ATP which is the main storage energy molecule in the cells.

How does ATP synthase allow production of ATP?

  • Production of ATP by ATP synthase complex is through oxidative level phosphorylation.
  • The flow of protons down the concentration gradient into the mitochondrion matrix through ATP synthase. This drives the rotation of   ATP synthase thus catalyzing the phosphorylation of ADP to ATP.
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Tim and Rick both can run at speed Vr and walk at speed Vw, with Vr > Vw.
miss Akunina [59]

Answer:

Δt =  \frac{2D}{Vw+Vr} - \frac{D}{2Vr} - \frac{D}{2Vw}

Explanation:

Hi there!

Using the equation of speed for the whole trip, we can obtain the time each one needed to cover the distance D.

The speed (v) is calculated by dividing the traveled distance (d) over the time needed to cover that distance (t):

v = d/t

Rick traveled half of the distance at Vr and the other half at Vw. Then, when v = Vr, the distance traveled was D/2 and the time is unknown, Δt1:

Vr = D/ (2 · Δt1)

For the other half of the trip the expression of velocity will be:

Vw = D/(2 · Δt2)

The total time traveled is the sum of both Δt:

Δt(total) = Δt1 + Δt2

Then, solving the first equation for Δt1:

Vr = D/ (2 · Δt1)

Δt1 = D/(2 · Vr)

In the same way for the second equation:

Δt2 = D/(2 · Vw)

Δt + Δt2 = D/(2 · Vr) + D/(2 · Vw)

Δt(total) = D/2 · (1/Vr + 1/Vw)

The time needed by Rick to complete the trip was:

Δt(total) = D/2 · (1/Vr + 1/Vw)

Now let´s calculate the time it took Tim to do the trip:

Tim walks half of the time, then his speed could be expressed as follows:

Vw = 2d1/Δt  Where d1 is the traveled distance.

Solving for d1:

Vw · Δt/2 = d1

He then ran half of the time:

Vr = 2d2/Δt

Solving for d2:

Vr · Δt/2 = d2

Since d1 + d2 = D, then:

Vw · Δt/2 +  Vr · Δt/2 = D

Solving for Δt:

Δt (Vw/2 + Vr/2) = D

Δt = D / (Vw/2 + Vr/2)

Δt = D/ ((Vw + Vr)/2)

Δt = 2D / (Vw + Vr)

The time needed by Tim to complete the trip was:

Δt = 2D / (Vw + Vr)

Let´s find the diference between the time done by Tim and the one done by Rick:

Δt(tim) - Δt(rick)

2D / (Vw + Vr) - (D/2 · (1/Vr + 1/Vw))

\frac{2D}{Vw+Vr} - \frac{D}{2Vr} - \frac{D}{2Vw} = Δt

Let´s check the result. If Vr = Vw:

Δt = 2D/2Vr - D/2Vr - D/2Vr

Δt = D/Vr - D/Vr = 0

This makes sense because if both move with the same velocity all the time both will do the trip in the same time.

8 0
3 years ago
Given the following specific heat capacities, which material was have the largest change in temperature if 10 grams of each subs
Ilya [14]

Answer:

Explanation:

Comment

You could calculate it out by assuming the same starting temperature for each substance. (You have to assume that the substances do start at the same temperature anyway).

That's like shooting 12 with 2 dice. It can be done, but aiming for a more common number is a better idea.

Same with this question.

You should just develop a rule.  The rule will look like this

The greater the heat capacity the (higher or lower) the change in temperature.

The greater the heat capacity the lower the change in temperature

That's not your question. You want to know which substance will have the greatest temperature change given their heat capacities.

Answer

lead. It has the smallest heat capacity and therefore it's temperature change will be the greatest.

5 0
2 years ago
Read 2 more answers
a rectangular coil of 25 loops is suspended in a field of 0.20wb/m2.the plane of coil is parallel to the direction of the field
statuscvo [17]

Answer:

The current in the coil is 60 Ampere.

Explanation:

Given:

Number of turns in the coil is N = 25

Dimension of the coil = 15cm X 12cm

magnitude of magnetic field = 0.20T

angle in the xy plane is θ = 0 degree

torque τ = 5.4 N-m

To find:

current in the coil is i = ?

Solution:

The torque acting on the coil is given by

=> \tau = NiAB cos\theta

Converting cm to m

12 cm = 0.12 m

15 cm = 0.15 m

The area of the coil is  

A = 0.12 X 0.15

A = 0.018 m^2

Substituting the values

=>5.4 = 25\times i \times 0.018 \times 0.20 \times cos\theta

=>5.4 = 25\times i \times 0.018 \times 0.20 \times cos(0)

=>5.4 = 25\times i \times 0.018 \times 0.20 \times 1

=>5.4 = 25\times i \times 0.018 \times 0.20 \times 1

=>5.4 = 0.09\times i

=>i = \frac{5.4}{0.09}

=> i = 60 A

3 0
3 years ago
4. ____________ occurs when one object slides over another.
hammer [34]

Answer:

A. Sliding friction

Explanation:

Sliding friction is weaker than static friction

8 0
3 years ago
Read 2 more answers
A body is piloted at a point. A force of 10 N is applied at a distance of 30 cm from the pivot. Find the amount of force about t
bekas [8.4K]

Question :-

  • A Body is Pivoted at a Point. A Force of 10 N is Applied at a Distance of 30 cm from the Pivot. Find the Amount of Force about the Pivot.

Answer :-

  • Amount of Force is 3 Nm .

Explanation :-

As per the provided information in the given question, The Force is given as 10 Newton . The Distance is given as 30 cm [ 0.3 m ] . And, we have been asked to calculate the Amount of Force .

For calculating the Force , we will use the Formula :-

\bigstar \:  \:  \:  \boxed{ \:  \sf {Moment \: of \: Force \:  =  \: Force \:  \times  \: Distance} \: }

Therefore , by Substituting the given values in the above Formula :-

\dag \:  \:  \: \sf {Moment \: of \: Force \:  =  \: Force \:  \times  \: Distance}

\longmapsto \:  \:  \: \sf {Moment \: of \: Force \:  =  \: 10 \:  \times  \: 0.3}

\longmapsto \:  \:  \: \textbf {\textsf {Moment \: of \: Force \:  =  \: 3}}

Hence :-

  • Amount of Force = 0.3 Nm .

\underline {\rule {185pt}{4pt}}

8 0
2 years ago
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