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SpyIntel [72]
3 years ago
10

The ATP synthase complex allows ATP production by A. proton-driven rotation of the Fo subunit, which causes F1 to change conform

ation due to that rotation, allowing ADP to be phosphorylated to ATP. B. substrate-level phosophorylation. C. generating the adenosine to produce ATP. D. pumping electrons across the membrane at the end of an ETS
Physics
1 answer:
zloy xaker [14]3 years ago
3 0

Answer:

A. proton-driven rotation of the Fo subunit, which causes F1 to change conformation due to that rotation, allowing ADP to be phosphorylated to ATP

Explanation:

To answer the question we need to understand the following.

What is ATP synthase?

  • ATP synthase is an enzyme that is found in the electron transport chain which is the final phase of cellular respiration.

What is the Role of ATP synthase?

  • The role of ATP synthase is to synthesize ATP which is the main storage energy molecule in the cells.

How does ATP synthase allow production of ATP?

  • Production of ATP by ATP synthase complex is through oxidative level phosphorylation.
  • The flow of protons down the concentration gradient into the mitochondrion matrix through ATP synthase. This drives the rotation of   ATP synthase thus catalyzing the phosphorylation of ADP to ATP.
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An electron with a charge value of 1.6x10^-19 C is in the presence of an electric field of 300 N/C when located between a pair o
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6 0
4 years ago
You used a telescope and other mathematics to discover that Jupiter is 5.20 au from the sun. Use the equation to find its orbita
meriva

Answer:

11.9 years

Explanation:

We can find the orbital period by using Kepler's third law, which states that the ratio between the square of the orbital period and the cube of the average distance of a planet from the Sun is constant for every planet orbiting aroudn the Sun:

\frac{T^2}{r^3}=const.

Using the Earth as reference, we can re-write the law as

\frac{T_e^2}{r_e^2}=\frac{T_j^2}{r_j^3}

where

Te = 1 year is the orbital period of the Earth

re = 1 AU is the average distance of the Earth from the Sun

Tj = ? is the orbital period of Jupiter

rj = 5.20 AU is the average distance of Jupiter from the Sun

Substituting the numbers and re-arranging the equation, we find:

T_j=\sqrt{\frac{T_e^2 r_j^3}{T_j^2}}=\sqrt{\frac{(1 y)^2 (5.2 AU)^3}{(1 AU)^3}}=11.9 y


4 0
3 years ago
Read 2 more answers
In a closed system, _____ energy is equal to potential energy plus kinetic energy.
Kobotan [32]
The answer is mechanical
4 0
4 years ago
Read 2 more answers
8. An unpowered flywheel is slowed by a constant frictional torque. At time t = 0 it has an angular velocity of 200 rad/s. Ten s
allsm [11]

Answer:

a) \omega = 50\,\frac{rad}{s}, b) \omega = 0\,\frac{rad}{s}

Explanation:

The magnitude of torque is a form of moment, that is, a product of force and lever arm (distance), and force is the product of mass and acceleration for rotating systems with constant mass. That is:

\tau = F \cdot r

\tau = m\cdot a \cdot r

\tau = m \cdot \alpha \cdot r^{2}

Where \alpha is the angular acceleration, which is constant as torque is constant. Angular deceleration experimented by the unpowered flywheel is:

\alpha = \frac{170\,\frac{rad}{s} - 200\,\frac{rad}{s} }{10\,s}

\alpha = -3\,\frac{rad}{s^{2}}

Now, angular velocities of the unpowered flywheel at 50 seconds and 100 seconds are, respectively:

a) t = 50 s.

\omega = 200\,\frac{rad}{s} - \left(3\,\frac{rad}{s^{2}} \right) \cdot (50\,s)

\omega = 50\,\frac{rad}{s}

b) t = 100 s.

Given that friction is of reactive nature. Frictional torque works on the unpowered flywheel until angular velocity is reduced to zero, whose instant is:

t = \frac{0\,\frac{rad}{s}-200\,\frac{rad}{s} }{\left(-3\,\frac{rad}{s^{2}} \right)}

t = 66.667\,s

Since t > 66.667\,s, then the angular velocity is equal to zero. Therefore:

\omega = 0\,\frac{rad}{s}

7 0
3 years ago
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