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2 years ago

Gravity and magnetism are both

Physics

2 answers:

ella [17]2 years ago

3 0

Answer:

Explanation:

Comment

You have to read this carefully enough that you don't mix up energy and forces.

Gravity is a force. If you don't believe me try jumping off a building. Which way are you going to go and why? Down because gravity attracts your mass.

So Magnetism must be a force as well. It acts in one direction, but not a specific one the way gravity acts). It also either attracts or repulses (pushes an object away)

Answer A

NeTakaya2 years ago

3 0

Common Forces

Common Forces

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How is a mixture different from a compound

aksik [14]

Answer:

Compounds are two or more elements chemically combined in definite proportions by weight.

Mixtures are two or more substances not chemically combined.

Explanation:

Hope this helped Mark BRAINLIEST!!!

6 0

3 years ago

A particle of mass m = 13 kg moves in space under the action of a conservative force. Its potential energy is given by PE = 2xyz

Helen [10]

Answer:

$F_{x}$ = -12 N , $F_{y}$ = -80 N and $F_{z}$ = - 44 N

Explanation:

The force is related to the potential energy by the formula

F = -Δ U = - ( $\frac{dU}{dx}$ i ^ + $\frac{dU}{dy}$ j ^ + $\frac{dU}{dz}$ k ^)

It indicates the potential energy

U = 2xyz + 3z² + 4yx + 16

To solve this problem let's make the derivatives, to find each component of the force

$\frac{dU}{dx}$ = 2yz + 0 + 4y + 0 = 2yz + 4y

$\frac{dU}{dx}$ = 2xz + 0 + 4x + 0 = 2xz + 4x

$\frac{dU}{dx}$ = 2xy + 3 2z + 0 +0 = 2xy + 6z

We look for the expression for the force in each axis

$F_{x}$ = - 2yz - 4y

$F_{y}$ = -2xz -4x

$F_{z}$ = -2xy -6z

We calculate at the point P = (20 i ^ + 1j ^ + 4 k ^) m

$F_{x}$ = - 2 1 4 - 4 1

$F_{x}$ = -12 N

$F_{y}$ = - 2 20 4 - 4 20

$F_{y}$ = -80 N

$F_{z}$ = - 20 1 - 6 4

$F_{z}$ = - 44 N

We put together the expression for strength

F = (-12 i ^ - 80j ^ -44k ^) N

5 0

4 years ago

If 1.34 ✕ 1020 electrons move through a pocket calculator during a full day's operation, how many coulombs of charge moved throu

ioda

Given :

Number of operations move through a pocket calculator during a full day's operation , $n=1.34 \times 10^{20}$ .

To Find :

How many coulombs of charge moved through it .

Solution :

We know , charge in one electron is :

$e^-=-1.6\times 10^{-19}\ coulombs$

So , charge on n electron is :

$C=e^-\times n\\C=-1.6\times 10^{-19}\times 1.34\times 10^{20} \ C\\C=-21.44\ C$

Therefore , -21.44 coulombs of charge is moved through it .

Hence , this is the required solution .

3 0

3 years ago

A parallel plate capacitor is charged up by a battery. The battery is then disconnected, but the charge remains on the plates. T

larisa [96]

Answer:

a. Decreases

b. Increases

c. Remains the same

d. Increases

Explanation:

a. Capacitance is given by c= Ak€/d

where A is conductivity plate with Area

K is a constant

€ is dielectric with permittivity.

d is the distance

b. Potential difference is given by

V = Ed, since, the electric field remains the

same, the potential diterence also increases with increase in distance.

Since the capacitance depends upon the distance, and all the other factors are kept constant, the capacitance decreases.

c. Electric field remains the same because charge on the

plate remains the same.

d. since electric field remains the same and capacitance decreases, the energy increases.

E= 1/2c * Q^2

7 0

4 years ago

A 0.0208 m diameter coin rolls up a 18.0◦ inclined plane. The coin starts with an initial angular speed of 56.0 rad/s and rolls

anastassius [24]

Answer:

h = 0.0259 m

Explanation:

given,

diameter of the cone = 0.0208 m

radius,r = 0.0104 m

angle of inclination,θ = 18°

initial angular velocity, ω_i = 56 rad/s

final angular velocity ,ω_f = 0 rad/s

height, h = ?

Rotational kinetic energy

$KE_r = \dfrac{1}{2}I\omega^2$

Moment of inertia of coin

$I = \dfrac{1}{2}MR^2$

so,

$KE_r = \dfrac{1}{4}MR^2\omega^2$

Transnational Kinetic energy

$KE_t = \dfrac{1}{2}Mv^2$

v = r ω

$KE_t = \dfrac{1}{2}MR^2\omega^2$

now,

using conservation energy

Kinetic energy of the coin is converted into the potential energy

KE_r + KE_t = PE

$\dfrac{1}{4}MR^2\omega^2 + \dfrac{1}{2}MR^2\omega^2 = Mgh$

$\dfrac{3}{4}R^2\omega^2=gh$

$\dfrac{3}{4}\times 0.0104^2\times 56^2=9.8\times h$

h = 0.0259 m

Vertical height gain by the coin is equal to 0.0259 m

7 0

4 years ago