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3 years ago

6

To test the hypothesis above, you will observe the changes during the experiment. To do this, you will use these observations to

compare the of the substances to the of the substances.

2 answers:

julsineya [31]3 years ago

8 0

^^ correct

Answer:

For the second part, select all of them

Explanation:

100%

wariber [46]3 years ago

4 0

The answer to this is initial appearance and the second is final appearance.

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A 51.0 kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 10.0 m th

shepuryov [24]

Answer:

The final speed of the crate is 12.07 m/s.

Explanation:

For the first 10.0 meters, the only force acting on the crate is 225 N, so we can calculate the acceleration as follows:

$F = ma$

$a = \frac{F}{m} = \frac{225 N}{51.0 kg} = 4.41 m/s^{2}$

Now, we can calculate the final speed of the crate at the end of 10.0 m:

$v_{f}^{2} = v_{0}^{2} + 2ad_{1}$

$v_{f} = \sqrt{0 + 2*4.41 m/s^{2}*10.0 m} = 9.39 m/s$

For the next 10.5 meters we have frictional force:

$F - F_{\mu} = ma$

$F - \mu mg = ma$

So, the acceleration is:

$a = \frac{F - \mu mg}{m} = \frac{225 N - 0.17*51.0 kg*9.81 m/s^{2}}{51.0 kg} = 2.74 m/s^{2}$

The final speed of the crate at the end of 10.0 m will be the initial speed of the following 10.5 meters, so:

$v_{f}^{2} = v_{0}^{2} + 2ad_{2}$

$v_{f} = \sqrt{(9.39 m/s)^{2} + 2*2.74 m/s^{2}*10.5 m} = 12.07 m/s$

Therefore, the final speed of the crate after being pulled these 20.5 meters is 12.07 m/s.

I hope it helps you!

7 0

3 years ago

The force on a dropped apple hitting the ground depends upon

yulyashka [42]

Answer:

F=ma

Explanation:

Force = mass * acceleration

5 0

3 years ago

A newly discovered particle, the SPARTYON, has a mass 945 times that of an electron. If a SPARTYON at rest absorbs an anti-SPART

Gennadij [26K]

Answer:

$\nu =1166\times 10^{20}Hz$

Explanation:

We have given the rest mass of SPARTYON = 945 times of mass of electron

We know that mass of electron $=9.11\times 10^{-31}kg$

So mass of SPARTYON $=945\times 9.11\times 10^{-31}=8608.95\times 10^{-31}kg$

Speed of light $c=3\times 10^8m/sec$

According to Einstein equation energy is given by

$E=mc^2=8608.95\times 10^{-31}\times (3\times 10^{8})^2=77480.55\times 10^{-15}j$

Now according to planks's rule

Energy is given by

$E=h\nu$ , here h is plank's constant $h=6.6\times 10^{-34}$

So $77480.55\times 10^{-15}=6.6\times 10^{-34}\nu$

$\nu =1166\times 10^{20}Hz$

3 0

3 years ago

If I toot 88 times what did that mean

Degger [83]

Answer:Nazi skinhead code for Heil Hitler. H being the 8th letter of the alphabet, therefore HH=88.

Explanation:

8 0

3 years ago

Find the voltage

son4ous [18]

Answer:

Explanation:

solve the parallel resistances

30||40 and 50||30

17.14285714 and 18.75

total Resistance = 35.89285714

V = IR

9V = I *35.89285714

9V / 35.89285714 = I

0.250746 = I

Now use the resistance across AB

V = 17.14285714 * 0.250746

V = 4.29850

this is the Voltage drop across AB :P

5 0

3 years ago