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cupoosta [38]
3 years ago
8

Pam, when she turned 25, made an investment of $20,000 at an interest rate of 6.5% compounded semi-annually. Now that she is 50

years old, how much is the investment worth now. A. $53,250 B. $44,491.96 C. $32,500 98,976.71
Engineering
1 answer:
Oxana [17]3 years ago
3 0

Answer:

D. $ 98,976.71

Explanation:

The formula for the future worth of the a present amount at compounding interest rate is given as:

FV = PV(1+r/n)^nt

where, (taking the age of 25 as present time and 50 years as future)

FV = Future Value = ?

PV = Present Value = $ 20,000

r = interest rate = 6.5% = 0.065

n = no. of periods within an year = 2

t = total no. of years passed = 50 - 25 = 25 years

Therefore,

FV = ($ 20,000)(1 + 0.065/2)^(2)(25)

<u>FV = $ 98,976.71</u>

Thus the correct answer is D. $ 98,976.71

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Explain the difference in the heat transfer modes of conduction and convection.
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Explanation:

Conduction is the heat transfer through a stationary matter by the physical contact.  

For example, the heat transferred between electric burner of stove and bottom of pan is transferred by the process of conduction.

Convection is heat transfer by macroscopic movement of the fluid. The particles of the fluid carry the current within themselves.  

For example, the water is the pot is warmed overall by heat transferred by the process of convection.

4 0
3 years ago
A voltage regulator is to provide a constant DC voltage Vl=10V to a load Rl from a nominal Vcc=15V supply voltage. The load can
Luden [163]

Answer:

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Beta=16-3/15=3/15=1/5=0.20

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3 years ago
In a shear cutting process, a sheet of soft cold-rolled steel has a thickness of 2 mm and a width of 1 m. The yield strength and
Ganezh [65]
Sorry I don’t know the answer I just need to answer some questions before I can get my own work done
6 0
3 years ago
2. Given that a quality-control inspection can ensure that a structural ceramic part will have no flaws greater than 100 µm (100
MA_775_DIABLO [31]

Answer:

SiC=169.26 Mpa

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Explanation:

<u>SiC </u>

Stress intensity, K is given by

K=\sigma Y\sqrt{\pi a} hence making \sigma the subject where \sigma is applied stress, Y is shape factor, a is crack length

\sigma=\frac {K}{Y\sqrt{\pi a}} substituting the given figures and assuming shape factor, Y of 1

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<u>Stabilized zirconia </u>

Stress intensity, K is given by

K=\sigma Y\sqrt{\pi a} hence making \sigma the subject where \sigma is applied stress, Y is shape factor, a is crack length

\sigma=\frac {K}{Y\sqrt{\pi a}} substituting the given figures and assuming shape factor, Y of 1

\sigma=\frac {9}{1\sqrt{\pi 100*10^{-6}}}= 507.7706\approx 507.77 Mpa

7 0
3 years ago
Which do you think would cause the most destruction to the organisms in a food web: taking away the carnivores, taking away the
kotegsom [21]

Answer:

Explanation:

I do not have access to your diagram but based on what I know, a food web cannot sustain itself without decomposers. They are the main guys who break down dead animals, plants into organic or inorganic nutrients which are needed by the primary producers to grow. So if decomposers are not there then producers cannot produce and thus herbivores cannot live and carnovers die out as well. Hope this makes sense.

Check out: https://www.nationalgeographic.org/encyclopedia/decomposers/

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3 years ago
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