Answer:
1. Buy Quiet – select and purchase low-noise tools and machinery
2. Maintain tools and equipment routinely (such 3. as lubricate gears)
3. Reduce vibration where possible
4. Isolate the noise source in an insulated room or enclosure
5. Place a barrier between the noise source and the employee
6. Isolate the employee from the source in a room or booth (such as sound wall or window
Explanation:
Hope my answer will help u.
Answer:
a( contractors need to know the amount of markup)
because the contractor should have a long term vision for a proper satisfaction to the people.
Answer:
1970
Explanation:
the answer must enough 20 character, so I...
Answer:
diameter is 14 mm
Explanation:
given data
power = 15 kW
rotation N = 1750 rpm
factor of safety = 3
to find out
minimum diameter
solution
we will apply here power formula to find T that is
power = 2π×N×T / 60 .................1
put here value
15 ×
= 2π×1750×T / 60
so
T = 81.84 Nm
and
torsion = T / Z ..........2
here Z is section modulus i.e = πd³/ 16
so from equation 2
torsion = 81.84 / πd³/ 16
so torsion = 416.75 / / d³ .................3
so from shear stress theory
torsion = σy / factor of safety
so here σy = 530 for 1020 steel
so
torsion = σy / factor of safety
416.75 / d³ = 530 ×
/ 3
so d = 0.0133 m
so diameter is 14 mm