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3 years ago

How many moles of water are in 1.23 x 10 to the 18th power water molecules

Chemistry

2 answers:

Ksivusya [100]3 years ago

6 0

Answer:

The answer is 2.04x10^-6 moles of water.

Explanation:

Avogadro's number is defined as the number of particles found in an amount of substance per mole. It is the factor that relates the moles of a substance to the mass of that substance. We will use Avogadro's number to calculate the number of moles of water. as follows:

Avogadro's number = 1 mol = 6.022 x 10^23 particles.

we will use the conversion factor to calculate the number of moles of water:

Moles of water = 1.23x10^18 particles x (1mol/6.022x10^23 particles) = 2.04x10^-6 moles

mamaluj [8]3 years ago

3 0

Divide the number of molecules you have by, 6.022 x 10^23. This will give you the moles of water, or the moles of anything, since there is always 6.022 x 10^23 molecules in 1 mole of substance.

1.23x10^24 atoms/6.022x10^23 atom/mole = 2.04 mole H20

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It takes to break an carbon-chlorine single bond. Calculate the maximum wavelength of light for which an carbon-chlorine single

Maslowich

Answer:

It takes approximately $5.43\times 10^{-19}\; \rm J$ of energy to break one $\rm C-Cl$ single bond.

The maximum wavelength of a photon that can break one such bond is approximately $3.66\times 10^{-7}\; \rm m$ (in vacuum.) That's the same as $3.66 \times 10^{2}\; \rm nm$ (rounded to three significant figures.)

Explanation:

<h3>Energy per bond</h3>

The standard bond enthalpy of $\rm C-Cl$ single bonds is approximately $\rm 327\; \rm kJ \cdot mol^{-1}$ (note that the exact value can varies across sources.) In other words, it would take approximately $327\; \rm kJ$ of energy to break one mole of these bonds.

The Avogadro Constant $N_A \approx 6.023\times 10^{23}\; \rm mol^{-1}$ gives the number of $\rm C-Cl$ bonds in one mole of these bonds. Based on these information, calculate the energy of one such bond:

$\begin{aligned}& E(\text{one $\mathrm{C-Cl}$ bond}) \\ &= \frac{E(\text{one mole of $\mathrm{C-Cl}$ bonds})}{N_A} = \frac{327\; \rm kJ\cdot mol^{-1}}{6.023\times 10^{23}\; \rm mol^{-1}} \\ &\approx 5.429\times 10^{-22}\; \rm kJ = 5.429\times 10^{-19}\; \rm J \end{aligned}$ .

Therefore, it would take approximately $5.43\times 10^{-19}\; \rm J$ of energy to break one $\rm C-Cl$ single bond.

<h3>Minimum frequency and maximum wavelength </h3>

The Einstein-Planck Relation relates the frequency $f$ of a photon to its energy $E$ :

$E = h \cdot f$ .

The $h$ here represents the Planck Constant:

$h \approx 6.63 \times 10^{-34}\; \rm J \cdot s$ .

A photon that can break one $\rm C-Cl$ single bond should have more than $5.43\times 10^{-19}\; \rm J$ of energy. Apply the Einstein-Planck Relation to find the frequency of a photon with exactly that much energy:

$\begin{aligned}f &= \frac{E}{h}\\ &\approx \frac{5.43\times 10^{-19}\; \rm J}{6.63 \times 10^{-34}\; \rm J\cdot s} \\ &\approx 8.19 \times 10^{14}\; \rm s^{-1} = 8.19 \times 10^{14}\; \rm Hz\end{aligned}$ .

What would be the wavelength $\lambda$ of a photon with a frequency of approximately $8.19 \times 10^{14}\; \rm Hz$ ? The exact answer to that depends on the medium that this photon is travelling through. To be precise, the exact answer depends on the speed of light in that medium:

$\displaystyle \lambda = \frac{(\text{speed of light})}{f}$ .

In vacuum, the speed of light is $c \approx 2.998\times 10^{8}\; \rm m \cdot s^{-1}$ . Therefore, the wavelength of that $8.19 \times 10^{14}\; \rm Hz$ photon in vacuum would be:

$\begin{aligned} \lambda &= \frac{c}{f} \\ & \approx \frac{2.998\times 10^{8}\; \rm m \cdot s^{-1}}{8.19\times 10^{14}\; \rm s^{-1}} \\ &\approx 3.66 \times 10^{-7}\; \rm m = 3.66 \times 10^{2}\; \rm nm\end{aligned}$ .

(Side note: that wavelength corresponds to a photon in the ultraviolet region of the electromagnetic spectrum.)

7 0

3 years ago

Please help!!!

e-lub [12.9K]

1) Compounds:

a) Chemically combined.

b) Components change properties.

c) Fixed proportions.

2) Mixtures:

a) Physically combined.

b) Components retain properties.

c) Variable proportions.

3) Both:

a) Made of elements.

b) 2 or more components.

A compound is a pure substance because its molecule cannot be broken down into simpler particles by physical means. For example water (H₂O) is a chemical compound made of two elements (hydrogen and oxygen).

In chemical change new substances are formed, the atoms are rearranged and the reaction is followed by an energy change.

There are no chemical bonds between substances in the mixture.,For example, mixture is solution of water and alcohol.

8 0

4 years ago

Read 2 more answers

Which term best describes an animal that eats dead and decaying meat? A. predator B. producer C. decomposer D. scavenger

marta [7]

These types of animals are referred to as D. scavengers.

Scavenger animals are adapted to feed on dead and decaying meat and usually feed on the carcasses left over by predatory animals. An example is how vultures pick off the meat from a zebra carcass that has been left over after a lion pack has finished eating from it.

8 0

4 years ago

Read 2 more answers

For each reaction, find the value of ΔSo. Report the value with the appropriate sign. (a) 3 NO2(g) + H2O(l) → 2 HNO3(l) + NO(g)

aev [14]

Answer:

ΔS° = -268.13 J/K

Explanation:

Let's consider the following balanced equation.

3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)

We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:

ΔS° = ∑np.Sp° - ∑nr.Sr°

where,

ni are the moles of reactants and products

Si are the standard molar entropies of reactants and products

ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]

ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]

ΔS° = -268.13 J/K

7 0

3 years ago

A horse runs 1 km in 15 s. What is the average speed

Reptile [31]

The average speed of the horse for the entire motion is 66.67 m/s.

The given parameters;

<em>distance traveled by the horse, d = 1 km = 1,000 m</em>
<em>time of motion of the horse, t = 15 s</em>

The average speed of the horse is calculated by dividing the total distance traveled by the horse by the time of motion.

The average speed of the horse is calculated as follows;

$average\ speed = \frac{distance}{time} \\\\average\ speed = \frac{1000 \ m}{15 \ s} = 66.67 \ m/s$

Thus, the average speed of the horse for the entire motion is 66.67 m/s.

Learn more here: brainly.com/question/17289046

6 0

3 years ago