The answer is c , between 52.43 and 64.20
Answer:
∠B = 62°
Step-by-step explanation:
Because ∠A and ∠B are vertical angles they are equal hence we can write
∠A = ∠B
8x + 14 = 2x + 50
Now we have to solve for x
To do so, subtract 2x on both sides of the equation:
6x + 14 = 50
Now, subtract 14 on both sides of the equation
6x = 36
Now, divide 6 on both sides of the equation
x = 6
To find m∠B you have to you have to plug in x = 6 back into the ∠B equation
∠B = 2(6) + 50
∠B = 62°
Yes a pair of angles can be both vertical and corresponding at the same time.
We know that
[area of a regular hexagon]=6*[area of one <span>equilateral triangle]
</span>210.44=6*[area of one equilateral triangle]
[area of one equilateral triangle]=210.44/6-----> 35.07 cm²
[area of one equilateral triangle]=b*h/2
h=7.794 cm
b=2*area/h------> b=2*35.07/7.794------>b= 9 cm
the length side of a regular hexagon is 9 cm
<span>applying the Pythagorean theorem
</span>r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm
<span>this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles)
</span>
the answer is
the radius is 9 cm
