The answer I got was 417/50 hope this helps you
Triangle B can be proven congruent
One way is to solve for the invers of the first function
remembe, to solve, replace f(x) or g(x) with y, switch x and y, solve for y and replace it with f⁻¹(x)
A.
f(x)=x/2+8
y=x/2+8
x=y/2+8
x-8=y/2
2x-16=y
f⁻¹(x)=2x-16
nope, not A
B.
f(x)=3x³+16
y=3x³+16
x=3y³+16
x-16=3y³
(x-16)/3=y³
∛((x-16)/3)=y
f⁻¹(x)=∛((x-16)/3)
nope, not the same
not B
C.
f(x)=18/x-9
y=18/x-9
x=18/y-9
x+9=18/y
y(x+9)=18
y=18/(x+9)
f⁻¹(x)=18/(x+9)
correct, the answer is C
answer is C
Answer:
Hope it helps bhhhhbbbbbbhb
Answer:
The probability that neither player gets on base is 0.4824
Step-by-step explanation:
1. Both players get to base. <em>Just multiply the two probabilities together</em>:
= (<em>probability first batter gets on base</em>) x (<em>probability second batter gets on base, if the first batter gets on base</em>)
= 0.23 x 0.38
= 0.0874
2. One player gets to base. The formula here is P(A+B) =P(A) + P(B) - P(A) x P(B)
= (<em>probability first batter gets on base</em>) + (<em>probability second batter gets on base, if the first batter does not</em>) - (0.23 x 0.26)
= 0.23 + 0.26 - (0.23 x 0.26)
= 0.49 - 0.0598
= 0.4302
3. Neither player gets to base =<em> 1 - addition of the previous two cases</em>.
= 1 - (0.0874 + 0.4302)
= 1 - 0.5176
= 0.4824
