Both are used to produce energy to be used as electricity
Answer: find the attached figure for a and b
Explanation:
A) The second figure depict electric field lines and equipotential lines for two equal but opposite charges. The equipotential lines can be drawn by making them perpendicular to the electric field lines. The potential is greatest (most positive) near the positive charge and least (most negative) near the negative charge.
B) The figure attached depicts an isolated point charge Q with its electric field lines in blue and equipotential lines in green. The potential is the same along each equipotential line, meaning that no work is required to move a charge anywhere along one of those lines. Work is needed to move a charge from one equipotential line to another. Equipotential lines are perpendicular to electric field lines in every case.
Please find the attached file for the figure
Answer:
A POSTAL PACKAGE IS PUSHED BY A HORIZONTAL TABLE WITH A FORCE F = 40N. PACKAGE MOVES ON A DISTANCE OF 1.5M WHICH MECHANICAL WORK PERFORMS THIS FORCE
PT TEST
To solve this problem it is necessary to apply the concepts related to the Force from Hook's law as well as the definition of the period provided by the same definition.
We know that the Force can be defined as

Where
k = Spring constant
x = Displacement
g = Gravity
m = mass
At the same time the period of a spring mass system is defined as

Where
m = Mass
k = Spring constant
Our values are given as,
m = 0.404kg
x = 0.666m
Replacing to find the value of the Spring constant we have that



Now using the formula of the period we know that



Finally, if the oscillation was 0.359m
The maximum height will be determined by the total length of that oscillation being equivalent to



Answer:
Volume flow rate = 
Explanation:
The volume flow rate through a channel can be gotten by multiplying its area and its velocity.
The channel under consideration is a circular channel. Hence, the cross-sectional area can be calculated by using the relation for calculating the area of a circle
Cross-sectional area = 

volume flow rate= 
Volume flow rate = 