Given that,
Angle = 30°
Initial velocity = 15 m/s
We need to calculate the time of flight
Using formula of time of flight
Where, u = initial velocity
g = acceleration due to gravity
Put the value into the formula
We need to calculate the final velocity of the ball
Using equation of motion
Hence, The final velocity of the ball is 29.7 m/s.
Answer:3
Explanation:
First ball is thrown with horizontal velocity while other ball is dropped from cliff such that both have zero vertical velocity. So both balls have to cover a distance equal to the height of cliff with same initial velocity.
time taken is given by
where h=height of cliff
g=acceleration due to gravity
horizontal velocity to first ball will make the ball to travel more horizontal distance as compared to second ball.
Option 3 is correct
There is no "why", because that's not what happens. The truth is
exactly the opposite.
Whatever the weight of a solid object is in air, that weight will appear
to be LESS when the object is immersed in water.
The object is lifted by a force equal to the weight of the fluid it displaces.
It displaces the same amount of air or water, and any amount of water
weighs more than the same amount of air. So the force that lifts the
object in water is greater than the force that lifts it in air, and the object
appears to weigh less in the water.
A) 300cm/h
B)1 hr=60 min
300/60=5
5cm/min
C)1m=100cm
300/100=3
3m/h