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valina [46]
3 years ago
9

Which is an example of sliding friction? (1 point)

Physics
2 answers:
irinina [24]3 years ago
5 0

Answer:

your answer is c

Explanation:

"a child applying the brakes on his bike"

Genrish500 [490]3 years ago
5 0

Answer:

Oa child applying the brakes on his bike

Explanation:

1. It is a rolling object, so no

2. is a gliding object

3. is  object going from a state rolling acceleration suddenly halted and it will slide this is the correct

4. again, it is rolling

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A cup of coffee is sitting on a table in a train that is moving with a constant velocity. The coefficient of static friction bet
Vikki [24]

Answer:

a = 2.94 m/s²

Explanation:

In order for the cup not to slip, the unbalanced force on cup must be equal to the frictional force:

Unbalanced Force = Frictional Force

ma = μR = μW

ma = μmg

a = μg

where,

a = maximum acceleration for the cup not to slip = ?

μ = coefficient of static friction = 0.3

g = acceleration due to gravity = 9.8 m/s²

Therefore,

a = (0.3)(9.8 m/s²)

<u>a = 2.94 m/s²</u>

3 0
3 years ago
What would happen to the amount of matter on earth if mass were not conserved during changes of state?
attashe74 [19]
<span>earth would be thrown off its balance and nature would be in danger of too many resources and not enough resources </span>
4 0
3 years ago
Read 2 more answers
Suppose you have two solid bars, both with square cross-sections of 1 cm2. They are both 24.6 cm long, but one is made of copper
vodka [1.7K]

Explanation:

Expression to calculate thermal resistance for iron (R_{I}) is as follows.

             R_{I} = \frac{L_{I}}{k_{I} \times A_{I}}  

where,   L_{I} = length of the iron bar

             k_{I} = thermal conductivity of iron

             A_{I} = Area of cross-section for the iron bar

Thermal resistance for copper (R_{c}) = \frac{L_{c}}{k_{c} \times A_{c}}[/tex]

where,  L_{c} = length of copper bar

             k_{c} = thermal conductivity of copper

            A_{c} = Area of cross-section for the copper bar

Now, expression for the transfer of heat per unit cell is as follows.

           Q = \frac{(100^{o} - 0^{o}}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}

 Putting the given values into the above formula as follows.

       Q = \frac{(100^{o} - 0^{o})}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}

  = \frac{(100^{o} - 0^{o})}{21 \times 10^{-2} m[\frac{1}{73 \times 10^{-4}m^{2}} + \frac{1}{386 \times 10^{-4}m^{2}}}

           = 2.92 Joule

It is known that heat transfer per unit time is equal to the power conducted through the rod. Hence,

                 P = \frac{Q}{T}

Here, T is 1 second so, power conducted is equal to heat transferred.

So,           P = 2.92 watt

Thus, we can conclude that 2.92 watt power will be conducted through the rod when it reaches steady state.

7 0
3 years ago
How far will a car travel in 30 min at 40 m/s? (kilometres)
kondor19780726 [428]

Answer:

72km

Explanation:

30 mins --> 30 x 60 s = 1800 s

Distance --> Speed x Time

= 40m/s x 1800s

= 72 000 m

= 72 km (1km is 1000m)

6 0
3 years ago
According to Newton's first law of motion, what would happen to a car traveling at a constant velocity of 55 MPH to the west in
mart [117]

Explanation:

  • Newton's first law of motion says that an object will be at rest or it will be in motion until an unbalanced force acts on it.
  • In this case, a car traveling at a constant velocity of 55 mph to the west in the absence of an unbalanced force.
  • It would mean that the car will continue to move with a constant velocity of 55 mph to the west due to Newton's first law of motion.
6 0
2 years ago
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