Answer:
It will take 313.376 sec to raise temperature to boiling point
Explanation:
We have given that potential difference V = 120 Volt
Current i = 4.50 A
So resistance 
Heat flow in resistor will be equal to 
It is given that this heat is used for boiling the water
Mass of the water = 0.525 kg = 525 gram
Specific heat of water 4.186 J/gram/°C
Initial temperature is given as 23°C
Boiling temperature of water = 100°C
So change in temperature = 100-23 = 77°C
Heat required to raise the temperature of water 
So 
t = 313.376 sec
So it will take 313.376 sec to raise temperature to boiling point
To solve this problem we must resort to the Work Theorem, internal energy and Heat transfer. Summarized in the first law of thermodynamics.

Where,
Q = Heat
U = Internal Energy
By reference system and nomenclature we know that the work done ON the system is taken negative and the heat extracted is also considered negative, therefore
Work is done ON the system
Heat is extracted FROM the system
Therefore the value of the Work done on the system is -158.0J
Answer:
Option C
Explanation:
According to the formula
So
If we use wide wire we increase the area of cross section so resistance decreases
Answer:
Explanation:
a) I = ½mR² = ½(19)(0.15²) = 0.21375 kg•m²
b) τ = Fnet(r) = (25 - 12)(0.15) = 1.95 N•m
c) CCW
d) a = τ/I = 1.95 / 0.21375 = 9.12280701... = 9.1 rad/s²
e) CCW