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3 years ago

8

Which number is right

1 answer:

KatRina [158]3 years ago

7 0

'C' is the correct choice. Please, do me a favor ... take a few minutes to read the other choices, A, B and D, and understand what's wrong with each of those. That's MUCH MUCH more important than knowing that C is correct.

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A collision at 30 mph will take any loose object in your car and give it the same force as if it were:

Sauron [17]

The answer is “Thrown”

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3 years ago

When hydrogen is heated or subjected to an electric discharge, it emits light with specific visible wavelengths. A diffraction g

BartSMP [9]

To solve this problem we will apply the concepts related to the double slit-experiment. For which we will relate the distance between the Slits and the Diffraction Angle with the order of the bright fringe and the wavelength, this is mathematically given as,

$d sin\theta = m\lambda$

Here,

d = Distance between Slits

m = Order of the fringes

$\lambda$ = Wavelength

$\text{Spacing between adjacent lines}$ = $d = 4926nm$

$\text{Wavelength of light} = \lambda = 656nm$

Rearranging to find the angle,

$sin\theta = \frac{m\lambda}{d}$

$\theta = sin^{-1}(\frac{m\lambda}{d})$

$\theta = sin^{-1}(\frac{(4)(656*10^{-9}m)}{4926*10^{-9}m})$

$\theta = 32.19\°$

Therefore the angle that the fourth order bright fringe occur for this specific wavelenth of light occur is 32.19°

3 0

3 years ago

In which atmosphere layer does 80 percent of the gas in the atmosphere<br> reside?

VladimirAG [237]

Answer: TheTroposphere contains 80% of the total gas in the atmosphere

7 0

3 years ago

Read 2 more answers

38.4 mol of krypton is in a rigid box of volume 64 cm^3 and is initially at temperature 512.88°C. The gas then undergoes isobari

kolbaska11 [484]

Answer:

Final volumen first process $V_{2} = 98,44 cm^{3}$

Final Pressure second process $P_{3} = 1,317 * 10^{10} Pa$

Explanation:

Using the Ideal Gases Law yoy have for pressure:

$P_{1} = \frac{n_{1} R T_{1} }{V_{1} }$

where:

P is the pressure, in Pa

n is the nuber of moles of gas

R is the universal gas constant: 8,314 J/mol K

T is the temperature in Kelvin

V is the volumen in cubic meters

Given that the amount of material is constant in the process:

$n_{1} = n_{2} = n$

In an isobaric process the pressure is constant so:

$P_{1} = P_{2}$

$\frac{n R T_{1} }{V_{1} } = \frac{n R T_{2} }{V_{2} }$

$\frac{T_{1} }{V_{1} } = \frac{T_{2} }{V_{2} }$

$V_{2} = \frac{T_{2} V_{1} }{T_{1} }$

Replacing : $T_{1} =786 K, T_{2} =1209 K, V_{1} = 64 cm^{3}$

$V_{2} = 98,44 cm^{3}$

Replacing on the ideal gases formula the pressure at this piont is:

$P_{2} = 3,92 * 10^{9} Pa$

For Temperature the ideal gases formula is:

$T = \frac{P V }{n R }$

For the second process you have that $T_{2} = T_{3}$ So:

$\frac{P_{2} V_{2} }{n R } = \frac{P_{3} V_{3} }{n R }$

$P_{2} V_{2} = P_{3} V_{3}$

$P_{3} = \frac{P_{2} V_{2}}{V_{3}}$

$P_{3} = 1,317 * 10^{10} Pa$

7 0

3 years ago

Match each chemical name with the correct chemical formula.

pochemuha

Is there any chemical names listed ?

4 0

3 years ago