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kumpel [21]
3 years ago
7

The number of perpandicular components of a force is​

Physics
1 answer:
Arturiano [62]3 years ago
3 0
Answer. 2 components

one directed upwards, and the other directed rightwards
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The plates of a spherical capacitor have radii 6.25 cm and 15.0 crn. The space between the two spheres is filled with a material
aleksklad [387]

Answer:

Capacitance is 0.572×10⁻¹⁰ Farad

Explanation:

Radius = R₁ = 6.25 cm = 6.25×10⁻² m

Radius = R₂ = 15 cm = 15×10⁻² m

Dielectric constant = k = 4.8

Electric constant = ε₀ = 8.854×10⁻¹² F/m

ε/ε₀=k

ε=kε₀

Capacitance\ (C)=\frac{4\pi k\epsilon_0 R_1\times R_2}{R_2-R_1}\\\Rightarrow C=\frac{4\pi 4.8\times 8.854\times 10^{-12}\times 15\times 10^{-2}\times 6.25\times 10^{-2}}{15\times 10^{-2}-6.25\times 10^{-2}}\\\Rightarrow C=0.572\times 10^{-10}\ Farad

∴ Capacitance is 0.572×10⁻¹⁰ Farad

3 0
2 years ago
Which is a vector quantity speed or velocity
Alecsey [184]
Velocity is a vector quantity. A vector quantity has both a magnitude and a direction. Speed only has a magnitude, but no direction. Velocity has both.
8 0
3 years ago
True or false: The therapeutic alliance is defined as the level of commitment a patient has to therapy.
Alik [6]

Answer:

False

Explanation:

it is indeed false

3 0
3 years ago
A rotating lens mechanism blocks the view of the object as the new lenses are rotated. Be sure to click each lense firmly into p
Jobisdone [24]

I think that mechanism is called a <em>"lens turret"</em>.

6 0
2 years ago
The total surface area of the human body is 1.20 m2 and the surface temperature is 30∘C=303∘K. If the surroundings are at a temp
zalisa [80]

To solve this problem we must consider the expressions of Stefan Boltzmann's law for which the rate of change of the radiation of energy H from a surface must be

H = Ae\sigma T^4

Where

A = Surface area

e = Emissivity that characterizes the emitting properties of the surface

\sigma = Universal constant called the Stefan-Boltzmann constant (5.67*10^{-8}m^{-2}K^{-4})

T = Absolute temperature

The total heat loss would be then

Q = H_2 -H_1

Q =Ae\sigma T_2^4-Ae\sigma T_1^4

Q = Ae\sigma (T_2^4-T_1^4)

Q = (1.2)(1)(5.67*10^{-8})(303^4-280^4)

Q = 155.29J

Therefore the net rate of heat loss from the body by radiation is 155.29J

8 0
2 years ago
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