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~ V.
Answer:
speed of electrons = 3.25 ×
m/s
acceleration in term g is 3.9 ×
g.
radius of circular orbit is 2.76 ×
m
Explanation:
given data
voltage = 3 kV
magnetic field = 0.66 T
solution
law of conservation of energy
PE = KE
qV = 0.5 × m × v²
v =
v =
v = 3.25 ×
m/s
and
magnetic force on particle movie in magnetic field
F = Bqv
ma = Bqv
a =
a =
a = 3.82 ×
m/s²
and acceleration in term g
a =
a = 3.9 ×
g
acceleration in term g is 3.9 ×
g.
and
electron moving in circular orbit has centripetal force
F =
Bqv =
r =
r =
r = 2.76 ×
m
radius of circular orbit is 2.76 ×
m
Answer:
585×10⁸ m
Explanation:
Distance = rate × time
d = (2.998×10⁸ m/s) (3.25 min) (60 s/min)
d = 585×10⁸ m
Answer:
r1 = 5*10^10 m , r2 = 6*10^12 m
v1 = 9*10^4 m/s
From conservation of energy
K1 +U1 = K2 +U2
0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2
0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2
M is mass of sun = 1.98*10^30 kg
G = 6.67*10^-11 N.m^2/kg^2
0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))
v2 = 5.35*10^4 m/s
Answer:
Oh I am sorry this is my first time on brainly i dont how to exit and sorry but dont know the answer
Explanation: