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BARSIC [14]
4 years ago
7

Consider the following data on some weak acids and weak bases:

Chemistry
1 answer:
Juli2301 [7.4K]4 years ago
8 0

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

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What is the chemical name of the compound represented by the formula Ni2O3? Use the list of polyatomic ions and the periodic tab
bearhunter [10]
The chemical name is nickel (III) oxide .
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3 years ago
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Why might having mud in an ecosystem be important?
Aloiza [94]

An insect needs mud wallows to breed; that insect pollinates several flowers in that ecosystem.

3 0
3 years ago
How many moles of Ammonium Sulfate can be made from 30.0mol of NH3? 2NH3 + H2SO4 --> (NH4)2SO4
BartSMP [9]

Answer: 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

Explanation:

The balanced chemical reaction is :

2NH_3+H_2SO_4\rightarrow (NH_4)_2SO_4

According to stoichiometry :

2 moles of NH_3 give = 1 mole of (NH_4)_2SO_4

Thus 30.0 moles of NH_3 will give =\frac{1}{2}\times 30.0=15.0moles  of (NH_4)_2SO_4

Thus 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

7 0
4 years ago
What part of a flowering plant becomes fruit?<br><br> seed<br> ovary<br> stem<br> spore
lord [1]

Answer:

the ovary

Explanation:

The fertilized ovule becomes the seed, and the ovary becomes the fruit. Petals are also important parts of the flower, because they help attract pollinators such as bees, butterflies and bats. You can also see tiny green leaf-like parts called sepals at the base of the flower.

4 0
4 years ago
Radioactive cobalt-60 is frequently used in treating cancer. It took 24 years for a 10 gram sample to decay to 0.625 grams. What
-BARSIC- [3]

Answer:

Half life is 6 years.

Explanation:

T½ = In2 / λ

Where λ = decay constant.

But N = No * e^-λt

Where N = final mass after a certain period of time

No = initial mass

T = time

N = 0.625g

No = 10g

t = 24 years

N = No* e^-λt

N / No = e^-λt

λ = -( 1 / t) In N / No (inverse of e is In. Check logarithmic rules)

λ = -(1 / 24) * In (0.625/10)

λ = -0.04167 * In(0.0625)

λ = -0.04167 * (-2.77)

λ = 0.1154

T½ = In2 / λ

T½ = 0.693 / 0.1154

T½ = 6.00 years.

The half life of radioactive cobalt-60 is 6 years

5 0
3 years ago
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