Answer:
1, 2, 4
Explanation:
The primitive cubic unit cell has eight corners, and each corner is shared with 8 cubic unit cells. Therefore since we have one atom at each corner, we will have:
8 corner x 1 atom/8 corner = 1 atom
There is then the equivalent of one atom per unit cell in the primitive cubic cell.
For the body-centered cubic unit cell, we have 8 corners again shared each by 8 lattices as in the simple cubic plus we have one atom in the center of the cubic lattice. Therefore, the number of atoms in the body -centerd unit cell is two:
8 corner x 1 atom/8 corner = 1 atom
+
1 atom in the center
= 2 atoms/ unit cel
For the face-centerd cubic again we have 8 atoms in the corners shared by 8 lattices, plus 1 atom in each of the faces shared by two unit cells:
8 corner x 1/8 atom/corner + 6 faces x 1 atom/face = 4 atoms/unit cell
Answer:
LiOH (aq) + VCl3(aq) ---> LiCl(aq) + V(OH)3(s) - unbalanced
3LiOH (aq) + VCl3(aq) ---> 3LiCl(aq) + V(OH)3(s) - balanced
3Li+OH- (aq) + V3+(Cl-)3(aq) ---> 3Li+Cl-(aq) + V3+(OH-)3(s) - showing ions
3Li+(aq) + 3OH- (aq) + V3+(aq) + 3Cl-(aq) ---> 3Li+(aq) + 3Cl-(aq) + V3+(OH-)3(s) (some courses don't show the charges in insoluble ionic compounds - so V(OH)3(s)) - Showing soluble ionic compounds as separate ions.
3OH- (aq) + V3+(aq) ---> V3+(OH-)3(s) (or V(OH)3(s)) - without spectator ions
Explanation:
i don't know if this is right ore not but i hope this helps even if it is just a little bit sorry if this does not help i truly apologize
The term formula units means molecules.
Then, what you are looking for is the mass in 4.59*10^24 molecules.
The procedure involves to convert the 4.59 * 10^24 molecules into moles and use the molar mass of the sodium chloride.
1) Number of moles = 4.59 * 10^24 molecules / (6.02 * 10^23 molecules/mol) = 7.62 mol
2) Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
3) mass of NaCl = molar mass * number of moles = 58.44 g/mol * 7.62 mol = 445.31 g of NaCl
Answer: 445.31 g of NaCl.
Answer:
46.8% should be. correct, I'm not fully sure though. : )
Answer:
The correct answer is 0.52 moles.
Explanation:
Based on the given question, 37 grams of magnesium reacts with 38 grams of HCl to produce MgCl2 or magnesium chloride. The reaction is:
Mg (s) + 2HCl (aq) ⇒ MgCl2 (aq) + H2 (g)
There is a need to find the theoretical yield in moles of MgCl2. The formula for calculating the no. or moles is mass/molar mass. Therefore, moles of magnesium is 37/24 = 1.54 and moles of HCl will be 38/36.5 = 1.04.
From the reaction it is clear that one mole of magnesium reacts with two moles of HCl, as lesser quantity of HCl is present in the given case, therefore, HCl will be the limiting reagent.
Now theoretical moles of magnesium chloride will be,
= moles of HCl / 2
= 1.04 / 2
= 0.52 moles