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12345 [234]
2 years ago
9

⚠️SOMEONE PLEASE HELP⚠️

Chemistry
2 answers:
Sliva [168]2 years ago
8 0

Answer:

D

Explanation:

I just took the test

pochemuha2 years ago
3 0

Answer:

Hey did u end up getting the answer by any chance ?

Explanation:

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Convert 125 g to kilograms
joja [24]
Move the decimal place to the left 3 digits.
0.125
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3 years ago
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When the Earth rotates, what happens to the constellations?
kobusy [5.1K]

Answer:

Constellations Changing Positions!!!!       :D  <----(smiley face)

Explanation:

Due to the earth's rotation, stars appear to move. As the Earth rotates from west to east, the stars appear to rise in the East, moving across south to set in the west. The Sun will appear to move through the stars, making one complete circuit of the sky in 365 days!!

(yes i'm literally 9+6 years old and idek why i'm doing this XD )

3 0
2 years ago
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The temperature and number of moles of a gas are held constant. Which of the following is true for the pressure of the gas?
Taya2010 [7]

Answer:

Pressure is inversely proportional to the volume of gas.

Explanation:

According to Boyle's law,

The volume of given amount of gas is inversely proportional to the pressure applied on gas at constant volume and number of moles of gas.

Mathematical expression:

P ∝ 1/ V

P = K/V

PV = K

when volume is changed from V1 to V2 and pressure from P1 to P2 then expression will be.

P1V1 = K         P2V2 = K

P1V1 = P2V2

3 0
3 years ago
What is the mRNA for TTGACAAGTTAC
sertanlavr [38]

Answer:

What is the question? I don't understand what you are trying to say.

3 0
2 years ago
A sample of gas has a density of 0.53 g/L at 225 K and under a pressure of 108.8 kPa. Find the density of the gas at 345 K under
sukhopar [10]

Answer:

\rho _2=0.22g/L

Explanation:

Hello!

In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:

PV=nRT\\\\PV=\frac{m}{MM} RT\\\\P*MM=\frac{m}{V} RT\\\\P*MM=\rho RT

Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:

\frac{P_1*MM}{P_2*MM} =\frac{\rho _1RT_1}{\rho _2RT_2} \\\\\frac{P_1}{P_2} =\frac{\rho _1T_1}{\rho _2T_2}

It means we can compute the final density as shown below:

\rho _2=\frac{\rho _1T_1P_2}{P_1T_2}

Now, we plug in to obtain:

\rho _2=\frac{0.53g/L*225K*68.3kPa}{345K*108.8kPa}\\\\\rho _2=0.22g/L

Regards!

8 0
2 years ago
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