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3 years ago

7

T+25=26 solve for t

2 answers:

kompoz [17]3 years ago

8 0

Answer: t = 1

Step-by-step explanation: To solve the equation <em>t + 25 = 26</em>, since 25 is being added to <em>t</em>, we need to subtract 25 from both sides of the equation.

On the left side of the equation, the +25 and -25 cancel each other out and we are simply left with <em>t</em>. On the right side, 25 - 26 is 1 so we have <em>t = 1</em> which is the solution to our equation.

pickupchik [31]3 years ago

4 0

Welcome!

Try writing the equation like this.

T = 26-25

Now, you need to simplify.

T= 1

You should get your final answer T = 1

You want to get T by itself, so you subtract 25 by itself to make it go away, but whatever you do to any side, you have to do it on the other side.

I apologize for the edits & mistakes I made. I've fixed them.

Sorry for any disturbance.

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Consider the graph of the function f(x) = 25

trasher [3.6K]

Considering it's horizontal asymptote, the statement describes a key feature of function g(x) = 2f(x) is given by:

Horizontal asymptote at y = 0.

<h3>What are the horizontal asymptotes of a function?</h3>

They are the limits of the function as x goes to negative and positive infinity, as long as these values are not infinity.

Researching this problem on the internet, the functions are given as follows:

$f(x) = 2^x$ .

$g(x) = 2f(x) = 2(2)^x$

The limits are given as follows:

$\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 2(2)^x = \frac{2}{2^{\infty}} = 0$

$\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 2(2)^x = 2(2)^{\infty} = \infty$

Hence, the correct statement is:

Horizontal asymptote at y = 0.

More can be learned about horizontal asymptotes at brainly.com/question/16948935

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2 years ago