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Over [174]
3 years ago
12

After 2 seconds the stone will have fallen a total of 19.6m how far will the stone have fallen after 5 seconds

Physics
2 answers:
Reil [10]3 years ago
6 0
After 5 seconds the stone will have fallen 49 m
nydimaria [60]3 years ago
4 0
49 m

Hope this helps
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The universal law of gravitation states that the force of attraction between two objects depends on which quantities?
Ronch [10]

Answer:

D. the masses of the objects and the distance between them

Explanation:

Gravitation is a force, a force doesn't care about the shape or density of objects, only about their masses... and distances.

And you can get it using the following equation:

f = \frac{Gm_{1}m_{2} }{d^{2} }

Where :

G is the universal gravitational constant : G = 6.6726 x 10-11N-m2/kg2

m represent the mass of each of the two objects

d is the distance between the centers of the objects.

4 0
3 years ago
If this decay has a half-life of 10.2 years, what mass of 60.8g carbon-14 will remain after 20.4 years
OLEGan [10]
20.4 years is 20.4/10.2 = 2 half-life cycles, which means a quarter of the starting mass or 15.2 g will remain after this time.
5 0
3 years ago
Dave and Alex push on opposite ends of a car that has a mass of 875 kg. Dave pushes the car to the right with a force of 250 N,
White raven [17]

The net force acting on the car is 65 N to the left

The net force acting on an object is simply defined as the resultant force acting on the object.

From the question given, we obtained the following data:

  • Force applied to the right (Fᵣ) = 250 N
  • Force applied to the left (Fₗ) = 315 N
  • Net force (Fₙ) =?

The net force acting on the car can be obtained as follow:

Fₙ = Fₗ – Fᵣ

Fₙ = 315 – 250

<h3>Fₙ = 65 N to the left </h3>

Therefore, the net force acting on the car is 65 N to the left

Learn more on net force: brainly.com/question/19549734

8 0
2 years ago
Read 2 more answers
If a ball is thrown vertically upward with a velocity of 80 ft/s, then its height after t seconds is s = 80t − 16t 2 . (a) what
MAXImum [283]
Max height occurs when v = 0.
v(t) = ds(t)/dt
v(t) = 80 - 32t
0 = 80 - 32t
t = 5/2

s(5/2) = 80(5/2) - 16(5/2)^2
s(5/2) = 100
Answer: 100 ft

96 = 80t - 16t²
t = 3, 2
(80 ± √256) / 32 using the quadratic equation.

v(2) = 16
v(3) = -16
4 0
3 years ago
IP The x and y components of a vector r⃗ are rx = 16 m and ry = -8.5 m , respectively
fiasKO [112]

as it is given that

r_x = 16 m

r_y = -8.5 m

now we will have

\vec r = 16 \hat i - 8.5 \hat j

now the magnitude of this vector is given as

|r| = \sqrt{16^2 + 8.5^2}

|r| = 18 m

now to find the direction we can use

tan\theta = \frac{r_y}{r_x}

tan\theta = \frac{-8.5}{16}

\theta = tan^{-1}(-0.53)

\theta = - 28^0

4 0
4 years ago
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