Answer: 3.4s
Explanation:
There are three stages in the motion of the ball, so you have to calculate the times for every stage.
1) Ball dropping from 9.5m: free fall
d = Vo + gt² / 2
Vo = 0 ⇒ d = gt² / 2 ⇒ t² = 2d / g = 2 × 9.5 m / 9.81 m/s² = 1.94 s²
⇒ t = √ (1.94 s²) = 1.39s
2) Ball rising 5.7m (vertical rise)
i) Determine the initial speed:
Vf² = Vo² - 2gd
Vf² = 0 ⇒ Vo² = 2gd = 2 × 9.81 m/s² × 5.7m = 111.8 m²/s²
⇒ Vo = 10.6 m/s
ii) time rising
Vf = Vo - gt
Vf = 0 ⇒ Vo = gt ⇒
t = Vo / g = 10.6 m/s / 9.81 m/s² = 1.08 s
3) Ball dropping from 5.7 m to 1.20m above the pavement (free fall)
i) d = 5.7m - 1.20m = 4.5m
ii) d = gt² / 2 ⇒ t² = 2d / g = 2 × 4.5 m / 9.81 m/s² = 0.92 s²
⇒ t = √ (0.92 s²) = 0.96s
4) Total time
t = 1.39s + 1.08s + 0.96s = 3.43s ≈ 3.4s
Answer:
i E=V/d=50/2*10^-3=25*10^3 N/C
ii It is a (+) and (-)
iii C=εA/d
C=12.56*10^-8 * 0.1/2*10^-4
C=62.83 μF
Q=CV=50*6.283*10^-6
Q=314 μC
iv E=0.5 QV
=0.5(50*314*10^-6)
=7850 μJoule
Explanation:
The trash bag will gain gain speed in till hitting the ground and passably exploding on impact of the ground depending on the strength of the trash bag it may rip during the fall.
If this was not what you were looking for please explain what you need in more detail.
Answer:
A , power
Explanation:
Hope this is useful. Have a lovely rest of your day! God bless you.
Answer: net primary productivity
Explanation: i just took my test and this was correct!
