Light through a vacuum. According to an official government sight, <em>nothing</em> travels faster than light through a vacuum.
Answer:
a) The voltage in an european house is 2,17 times greater than in an american House. That is 183 volts more than in US.
b) the number of cycles or oscillations for an US House is 60 cycles per second
Explanation:
To answer this this question you have to know the wave equation:
x(t) = A Sin (a + b.t)
where
x(t) = is the position as a time function... In this exercise we could call V(t) instead of x(t) beacause we want to know voltage vs time.
A = is the amplitude of the wave. In this case the maximum voltage that can be reached.
a = is the offset in time or number of waves (zero in this exercise)
b = constant that varies the frequency
then...
a) calculate the ratio between both amplitudes:

b) frequency (Oscillations) is:
b = 2pi/T = 2pi*F remember that: T = 1/F
where
F = frequency
T = Period
so for US household we have:
120pi =2pi*F
therefore
F = 120/2 = 60 Hertz
Answer:

Explanation:
The speed of the actor before the collision is found by means of the Principle of Energy Conservation:



The speed after the inelastic collision is obtained by using the Principle of Momentum Conservation:


Lastly, the maximum height is determined by using the Principle of Energy Conservation again:



When you touch a doorknob (or something else made of metal), which has a positive charge with few electrons, the extra electrons want to jump from you to the knob. That tiny shock you feel is a result of the quick movement of these electrons.
The shot putter should get out of the way before the ball returns to the launch position.
Assume that the launch height is the reference height of zero.
u = 11.0 m/s, upward launch velocity.
g = 9.8 m/s², acceleration due to gravity.
The time when the ball is at the reference position (of zero) is given by
ut - (1/2)gt² = 0
11t - 0.5*9.8t² = 0
t(11 - 4.9t) = 0
t = 0 or t = 4.9/11 = 0.45 s
t = 0 corresponds to when the ball is launched.
t = 0.45 corresponds to when the ball returns to the launch position.
Answer: 0.45 s