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Goshia [24]
4 years ago
11

A tow truck is pulling 25,000 kg van with a tow hook that meets the van at an angle of 30° with the ground. How much force must

the tow trucl use to pull the van with an initial acceleration of 3m/s2...!?
Physics
1 answer:
Law Incorporation [45]4 years ago
3 0

Answer:

86605.08 N

Explanation:

The equation to calculate the force is:

Force = mass * acceleration

The force and the acceleration does not have the same direction in this case, so we need to decompose the force into its horizontal component, which is the force that will generate the horizontal acceleration:

Force_x = Force * cos(30)

Then, we have that:

Force_x = mass * acceleration

Force * cos(30) = 25000 * 3

Force * 0.866 = 75000

Force = 75000 / 0.866 = 86605.08 N

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How long will it take take light moving at 300,000 km/s to reach us from the sun? The sun is 15,000,000 km from earth.
AysviL [449]
15,000,000/300,000=50
It will take 50 seconds.
6 0
3 years ago
A daredevil is shot out of a cannon at 31.4 ◦ to the horizontal with an initial speed of 25.9 m/s. A net is positioned a horizon
Tanzania [10]

Answer:

The net should be placed at a height of 8.45 m

Explanation:

In order to calculate the height you have to apply the equations of <em>projectil motion.</em>

For x-axis, the position at a time t is given by:

Xf=Xo +(VoCosα)t (I)

Where Xf is the final position, Xo is the initial position, Vo is the initial speed and t is the time.

For the y-axis, the position at a time t is given by:

Yf=Yo + (VoSinα)t - 0.5gt^{2} (II)

Where Yf is the final position, Yo is the initial position, Vo is the initial speed, t is the time and g is the acceleration of gravity.

For both equations, ∝ is the angle formed by the cannon and the horizontal

The height where the net should be placed in order to catch the daredevil is given by replacing the time when the daredevil will be in the horizontal position of 39.7 m in the equation of position for the y-axis.

So, you have to calculate the time using (I)

Let the system of reference be placed at x=o and y=o

Xf= 0 + 25.9Cos(31,4◦)t

Xf=39.7

39.7=22.1t

Dividing both sides by 22.1 to find the value of t:

t=1.79 seconds

Replacing the time in equation (II) to find the height:

Yf=0 +25.9Sin(31,4◦)(1.79) - 0.5(9.8)1.79^{2}

Yf= 8.45 m

So the height is 8.45 m

4 0
3 years ago
Calculating the acceleration of two people pulling a box with same force and angle.
Dmitriy789 [7]

Here as we can see there we be net horizontal force acting on it

F_x = F_1cos20 + F_2cos20

also we know that

F_1 = F_2 = 80 N

now we will have

F_x = 2(80cos20)

F_x = 150.35 N

now for net force of box we know

F_x - F_f = ma

150.35 - 100 = ma

20a = 50.35

a = 2.52 m/s^2

so acceleration of the box will be 2.52 m/s/s

7 0
3 years ago
why does the number 54289.00 have seven significant figures and not five? explain using the rules of significant figures
SCORPION-xisa [38]

The way I see it, depending on what the number represents, the number in the decimals spot could mean something significant. hope this helps :)

7 0
3 years ago
Read 2 more answers
Two railroad cars, each of mass 6500 kg and traveling 80 km/h in opposite directions, collide head-on and come to rest. how much
n200080 [17]
This problem can be assume that the two railroad cars are moving  toward each other, and not in opposite direction, because of the condition of an head collision.

Given: Mass of Car₁ = 6,500 Kg;  Mass of Car₂ = 6,500 Kg

           Velocity of each Car  V = 80 Km/h or 22.22 m/s

 Required: Thermal energy or Total Kinetic energy

Formula: K.E = 1/2 MV²

Solution: Total Kinetic energy or  Tke  = (1/2 MV²)car₁ + (1/2 MV²)car₂

Tke = 1/2 (6,500 Kg)(22.22 m/s)² + 1/2 (6,500 Kg)(22.22 m/s)²

Total Thermal energy or Tke = 3,209 Joules
8 0
3 years ago
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