Unidirectional and continuous carbon fibers with a diameter of 6.5 micron are embedded within an epoxy that offers a yield point
1 answer:
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Answer:
Explanation:
Given that solid circular rod rotates at constant speed and neglecting losses throughout the system, power is calculated as the product of torque and angular speed. That is to say:
There is a formula that relates torque with shear stress:
Where is the torsion module, whose formula for a solid circular cross section is:
The tension module is calculated herein:
Maximum allowed torsion is found by isolating it from shear stress equation:
Then, maximum transmissible power is determined directly:
Answer:
Please see attachment.
Explanation:
Answer:
Explanation:
Given data in question
mean stress = 50 MPa
amplitude stress = 225 MPa
to find out
maximum stress, stress ratio, magnitude of the stress range.
solution
we will find first maximum stress and minimum stress
and stress will be sum of (maximum +minimum stress) / 2
so for stress 50 MPa and 225 MPa
=
+
/ 2
50 = +
/ 2 ...........1
and
225 = +
/ 2 ...........2
from eqution 1 and 2 we get maximum and minimum stress
= 275 MPa ............3
and = -175 MPa ............4
In 2nd part we stress ratio is will compute by ratio of equation 3 and 4
we get ratio = /
ratio = -175 / 227
ratio = -0.64
now in 3rd part magnitude will calculate by subtracting maximum stress - minimum stress i.e.
magnitude = -
magnitude = 275 - (-175) = 450 MPa