A level loop began and closed on BM_A (elevation = 823.368 ft). The plus and minus sights were kept approximately equal. Reading
s (in feet) listed in the order taken are: 4.388 (BS) on BM_A, 4.538 (FS) and 6.907 (BS) on TP1, 8.8 (FS) and 4.68 (BS) on TP2, 5.978 (FS) and 3.73 (BS) on TP3, 5.245 (FS) and 8.464 (BS) on TP4, and 3.598 (FS) on BM_A.
Distances are: BM_A to TP1 = 375 ft, TP1 to TP2 = 212 ft, TP2 to TP3 = 402 ft, TP3 to TP4 = 257 ft, TP4 to BM_A = 254 ft.
The final (adjusted) height of TP2 is?
What is the observed height difference between TP2 and TP3 ?
The misclosure is?
The number of setups (n) is?
What is the provisional Height of TP3?
The precision (m) for the leveling run is equal to (rounded to nearest integer)
The correction for each set-up is?
Distances are: BM_A to TP1 = 375 ft, TP1 to TP2 = 212 ft, TP2 to TP3 = 402 ft, TP3 to TP4 = 257 ft, TP4 to BM_A = 254 ft.
The final (adjusted) height of TP2 is?
What is the observed height difference between TP2 and TP3 ?
The misclosure is?
The number of setups (n) is?
What is the provisional Height of TP3?
The precision (m) for the leveling run is equal to (rounded to nearest integer)
The correction for each set-up is?
1 answer:
You might be interested in
Answer:d
Explanation:
Given
Temperature
Also
R=287 J/kg
Flow will be In-compressible when Mach no.<0.32
Mach no.
(a)
Mach no.
Mach no.=0.63
(b)
Mach no.
Mach no.=0.31
(c)
Mach no.
Mach no.=1.27
(d)
Mach no.
Mach no.=0.127
From above results it is clear that for Flow at velocity 200 km/h ,it will be incompressible.
Same question idea but different values... I hope I helped you... Don't forget to put a heart mark
