A) gneiss
Explanation:
The likely rock that would be found here is gneiss.
A rock type that forms under a great deal of temperature and pressure is a metamorphic rock.
Such rocks would have their minerals crystallized when subjected to these extreme conditions.
- Metamorphic rocks are changed rocks that are formed when minerals in rocks are subjected to extreme pressure and temperature before they start melting.
- These rock type can form from either sedimentary or igneous rocks. In fact a metamorphic rock can also change into another one.
- Examples of metamorphic rocks are gneiss, schist, hornfels, marble etc.
Halite, limestone and sandstone are examples of sedimentary rocks that forms by the accumulation of sediments or precipitation of ions form solutions.
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Answer:
She must stop the car before interception, distance traveled 12.66 m
Explanation:
We will take all units to the SI system
Vo = 48Km / h (1000m / 1Km) (1h / 3600s) = 13.33 m / s
V2 = 70 Km / h = 19.44 m / s
We calculate the distance traveled before stopping
X = Vo t + ½ to t²
Time is what it takes traffic light to turn red is t = 2.0 s
X = 13.33 2 + 1.2 (-7) 2²
X = 12.66 m
It stops car before reaching the traffic light turning to red
Let's analyze what happens if you accelerate, let's calculate the acceleration of the vehicle
V2 = Vo + a t2
a = (V2-Vo) / t2
a = (19.44-13.33) /6.6
a = 0.926 m / s2
This is the acceleration to try to pass the interception, now let's calculate the distance it travels in the time the traffic light changes from yellow to red (t = 2.0 s)
X = Vo t + ½ to t²
X = 13.33 2 + ½ 0.926 2²
X = 28.58 m
Since the vehicle was 30 m away, the interception does not happen
Answer:
3.1 m/s
Explanation:
First, find the time it takes for the cat to land. Take down to be positive.
Given:
Δy = 0.61 m
v₀ = 0 m/s
a = 9.81 m/s²
Find: t
Δy = v₀ t + ½ at²
(0.61 m) = (0 m/s) t + ½ (9.81 m/s²) t²
t = 0.353 s
Now find the horizontal velocity needed to travel 1.1 m in that time.
Given:
Δx = 1.1 m
a = 0 m/s²
t = 0.353 s
Find: v₀
Δx = v₀ t + ½ at²
(1.1 m) = v₀ (0.353 s) + ½ (0 m/s²) (0.353 s)²
v₀ = 3.1 m/s
The tension in the string holding the tassel and the vertical will the tension in the string
<h3>What is the tension in the string holding the tassel. ?</h3>
Generally, the equation for Tension is mathematically given as
Therefore
T = 0.1953 N
b).
Where
a = 1.13 m/s^2
In conclusion
T* sinФ = ma
2msinФ = ma
2sinФ = a
Ф = 34.4 °
In conclusion, The tension in the string holding the tassel and the vertical will the tension in the string
T = 0.1953 N
Ф = 34.4 °
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