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serg [7]
1 year ago
6

Are there conditions under which the incident light ray undergoes reflection but not transmission at the boundary? if so, then w

hat are those conditions?
Physics
1 answer:
Luden [163]1 year ago
6 0

Total internal reflection causes light to be completely reflected across the  boundary between the two media but not transmitted.

<h3>What is total internal reflection?</h3>

The term total internal reflection occurs when light is moving from a denser to a less dense medium such as from glass to air. This phenomenon occurs at the interface between the two media.

There are two conditions necessary for total internal reflection and they are;

1) Light must travel from a denser to a less dense medium

2) The angle of incidence in the denser medium must be greater than the critical angle.

Total internal reflection causes light to be completely reflected across the  boundary between the two media but not transmitted.

Learn more about total internal reflection:brainly.com/question/13088998

#SPJ1

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If the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular
erastova [34]

Answer;

D. The car would begin to move in the direction it was headed in a straight line.

Explanation;

-Centripetal force is any net force causing uniform circular motion. The direction of a centripetal force is toward the center of curvature, the same as the direction of centripetal acceleration.

-The centripetal force causing the car to turn in a circular path is due to friction between the tires and the road. A minimum coefficient of friction is needed, or the car will move in a larger-radius curve and leave the roadway.

-Therefore,If the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular path were reduced then the car would begin to move in the direction it was headed in a straight line.

6 0
3 years ago
Read 2 more answers
If we put negative charge between two similar positive charges then what is it's equilibrium? And how?​
Gnesinka [82]

Your question has been heard loud and clear.

Well it depends on the magnitude of charges. Generally , when both positive charges have the same magnitude , their equilibrium point is towards the centre joining the two charges. But if magnitude of one positive charge is higher than the other , then the equilibrium point will be towards the charge having lesser magnitude.

Now , a negative charge is placed in between the two positive charges. So , if both positive charges have same magnitude , they both pull the negative charge towards each other with an equal force. Thus the equilibrium point will be where the negative charge is placed because , both forces are equal , and opposite , so they cancel out each other at the point where the negative charge is placed. However if they are of different magnitudes , then the equilibrium point will be shifted towards the positive charge having less magnitude.

Thank you

5 0
3 years ago
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Helpp me pleassee....
lilavasa [31]

Answer:

The fundamental wavelength of the vibrating string is 1.7 m.

Explanation:

We have,

Velocity of wave on a guitar string is 344 m/s

Length of the guitar string is 85 cm or 0.85 m

It is required to find the fundamental wavelength of the vibrating string. The fundamental frequency on the string is given by :

f=\dfrac{v}{2l}\\\\f=\dfrac{344}{2\times 0.85}\\\\f=202.35\ Hz

Now fundamental wavelength is :

\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{344}{202.35}\\\\\lambda=1.7\ m

So, the fundamental wavelength of the vibrating string is 1.7 m.

4 0
3 years ago
The speed of light in a solid is 1.24 x 108 m/s. <br> Calculate the index of refraction
Dahasolnce [82]

Answer:

125

Explanation:

7 0
2 years ago
A car is traveling north. can its acceleration vector ever Point South? explain​
Scrat [10]
Yes.

The acceleration vector WILL point south when the car is slowing down while traveling north

7 0
2 years ago
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