C because they are both going in a constant speed
Answer:
<h2>B. 20°</h2>
Explanation:
Range in projectile is defined as the distance covered in the horizontal direction. It is expressed as R = U²sin2Ф/g
U is the initial velocity of the body (in m/s)
Ф is the angle of projection
g is the acceleration due to gravity.
Given U = 14m/s, g = 9.8m/s and range R = 15 m
we will substitute this value into the formula to get the projection angle Ф as shown;
15 = 15²sin2Ф/9.8
15*9.8 = 15²sin2Ф
147 = 225sin2Ф
sin2Ф = 147/225
sin2Ф = 0.6533
2Ф = sin⁻¹0.6533
2Ф = 40.79°
Ф = 40.79°/2
Ф = 20.39° ≈ 20°
Hence, the range is greatest at angle 20°
The second law of thermodynamics states that the state of entropy of the entire universe, as an isolated system, will always increase over time. The second law also states that the changes in the entropy in the universe can never be negative.
<h3>
Answer:</h3>
375 N
<h3>
Explanation:</h3>
Topic tested: Newton's Law of motion
The question is testing on the application of Newton's second Law of motion.
We are given;
- Mass of the football = 5 Kg
- Initial velocity of the football, Vf = 15 m/s
- Time taken to bring the ball to rest = 0.2 s
- Final velocity, Vo = 0 m/s ( since the ball went to rest)
We are required to determine the force exerted to bring it to rest.
- According to the Newton's second law of motion the resultant force and rate of change in momentum are directly proportion.

Thus;


Force = 375 N
Hence, the force exerted on the ball by the receiver was 375 N