Answer:
Maximum energy of the capacitor,
Explanation:
It is given that,
Dielectric constant of the parallel plate capacitor, k = 4.14
Area of cross section of each plate,
Separation between the plates, d = 1.68 mm = 0.00168 m
The electric field between the plates,
Let E is the maximum energy that can be stored in the capacitor. Its formula is given by :
C is the capacitance of the capacitor,
V is the potential difference,
V = 369.6 volts
So, the maximum energy that can be stored in the capacitor is. Hence, this is the required solution.