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tester [92]
3 years ago
8

Properties of matter ---------------------------

Chemistry
2 answers:
Ivenika [448]3 years ago
7 0
The answer that fills in that blank would be the word Mass. "Mass is the measure of how much space an object takes up."
Elza [17]3 years ago
6 0
I do not know your lines are all messed up is that 2 words after matter or just 1
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What is constant on wet asphalt?
wariber [46]

Answer:

Friction and Automobile Tires. ... On dry surfaces you might get as high as 0.9 as a coefficient of friction, but driving them on wet roads would be dangerous since the wet road coefficient might be as low as 0.1

Explanation:

hope this helps

6 0
3 years ago
Harvey kept a balloon with a volume of 348 milliliters at 25.0˚C inside a freezer for a night. When he took it out, its new volu
ad-work [718]

Initial volume of the balloon = V_{1}= 348 mL

Initial temperature of the balloon T_{1} = 25.0^{0}C + 273 = 298 K

Final volume of the balloon V_{2} = 322 mL

Final temperature of the balloon = T_{2} = ?

According to Charles law, volume of an ideal gas is directly proportional to the temperature at constant pressure.

\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }

On plugging in the values,

\frac{348mL}{298 K} =\frac{322 mL}{T_{2} }

T_{2} =276 K

Therefore, the temperature of the freezer is 276 K

5 0
3 years ago
41 to
tia_tia [17]

Answer:

d = 0.9 g/L

Explanation:

Given data:

Number of moles = 1 mol

Volume = 24.2 L

Temperature = 298 K

Pressure = 101.3 Kpa (101.3/101 = 1 atm)

Density of sample = ?

Solution:

PV = nRT     (1)

n = number of moles

number of moles = mass/molar mass

n = m/M

Now we will put the n= m/M in equation 1.

PV = m/M RT   (2)

d = m/v

PM = m/v RT ( by rearranging the equation 2)

PM = dRT

d = PM/RT

The molar mass of neon is = 20.1798 g/mol

d = 1 atm × 20.1798 g/mol / 0.0821 atm. L/mol.K × 273K

d = 20.1798 g/22.413 L

d = 0.9 g/L

4 0
3 years ago
What is the name of the following compound? A line-angle formula shows a ring with six vertices and a circle inscribed. A Cl ato
ozzi

Answer: Option C. p-dichlorobenzene and 1,4-dichlorobenzene.

Explanation:

A line-angle formula with six vertices and a circle inscribed corresponds to the compound known as benzene.

Further, according to the IUPAC standards for naming benzene derivatives, you must first number the position of the substituent. In this case, the substituents (chloros) are located at the positions 1 and 4; also, for the benzene derivatives when they have 2 substituents and the positions are 1 and 4, this configuration is known as <em>para </em>or <em>p </em>configuration.

Additionally, this compound has 2 substituents (chloros) so you have to indicate this number (di).

Therefore, the correct answer is C. p-dichlorobenzene and 1,4-dichlorobenzene.

4 0
3 years ago
How the relative density of a substance is related to the density calculate the density of iron if its relative density is 2 and
il63 [147K]

Answer:

How the relative density of a substance is related to the density calculate the density of iron if its relative density is 2 and a density of water is 2gcm -3

R.d= relative density of substance/ relative density of water

R.d= 2/2

R.d= 1gcm-3

Explanation:

5 0
3 years ago
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