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KonstantinChe [14]
3 years ago
5

Which of these are physical changes in matter chech all that apply

Chemistry
2 answers:
Bogdan [553]3 years ago
8 0

Explanation:

Changes that are unable to bring any difference in chemical composition of a substance are known as physical change.

For example, change in shape, size, mass, volume, density, boiling or freezing point etc are all physical changes.

Whereas changes that bring difference in chemical composition of a substance are known as chemical changes.

For example, reactivity, toxicity, combustion etc are all chemical changes.

Hence, out of the given options physical changes are classified as follows.

  • Boiling water
  • A pencil being sharpened
  • Freezing water

serious [3.7K]3 years ago
6 0

Answer:

a pencil being sharpened

freezing water

boiling water

Explanation:

a physical change doesn't change the chemical structure of an object. That is why the other 2 are wrong

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A 7.74 L balloon is filled with water at 3.88 atm. If the balloon is squeezed into a 0.23 L beaker and does NOT burst, what is t
Vladimir [108]

Answer:

131 atm

Explanation:

To find the new pressure, you need to use Boyle's Law:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new pressure (P₂) by plugging the given values into equation and simplifying.

P₁ = 3.88 atm                       P₂ = ? atm

V₁ = 7.74 L                           V₂ = 0.23 L

P₁V₁ = P₂V₂                                                      <----- Boyle's Law

(3.88 atm)(7.74 L) = P₂(0.23 L)                       <----- Insert values

30.0312 = P₂(0.23 L)                                      <----- Simplify left side

131 = P₂                                                          <----- Divide both sides by 0.23

6 0
2 years ago
1) A common experiment to determine the relative reactivity of metallic elements is to place a pure sample of one metal into an
Annette [7]

Answer: Zn(s)+CuSO_4(aq)\rightarrow ZnSO_4+Cu

Explanation:-

Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.

As zinc is more reactive than copper, it could easily displace copper from its aqueous solution and thus leads to formation of zinc (II) sulfate and pure copper.

The chemical reaction can be represented as :

Zn(s)+CuSO_4(aq)\rightarrow ZnSO_4+Cu

The phases are represented as (s) for solid sate, (l) for liquid state, (g) for gaseous state and (aq) for aqueous state.

7 0
3 years ago
Read 2 more answers
Why Are aquifers important to our freshwater supply? 5TH GRADE ANSWER c:
ANEK [815]

Explanation:

Aquifers are porous and permeable formations that stores ground water. The ground water system is made up of mostly fresh water.

  • An aquifer acts as a reserve for ground water in the environment.
  • By passing through different formations, water that recharges them are purified.
  • This makes them fresh and mostly free from salt intrusion

An aquifer is able to store this fresh water and it is is good prospect for sourcing ground water.

4 0
3 years ago
Convert the following masses into kilograms:
beks73 [17]

Answer:

(a): 2,300 kilograms

(b): 0.005 kilograms

(c): 2.3 × 10^-5 kilograms

(d): 155 kilograms

Explanation:

Formulas:

(a); divide the mass value by 1000

(b); divide the mass value by 1e+6

(c); divide the mass value by 1e+9

(d); multiply the mass value by 1000

5 0
3 years ago
A 1.450 g sample of an unknown organic compound , X, is dissolved in 15.0 g of toluene
muminat

Answer:

Molecular weight of the compound = 372.13 g/mol

Explanation:

Depression in freezing point is related with molality of the solution as:

\Delta T_f = K_f \times m

Where,

\Delta T_f = Depression in freezing point

K_f = Molal depression constant

m = Molality

\Delta T_f = K_f \times m

1.33 = 5.12 \times m

m = 0.26

Molality = \frac{Moles\ of\ solute}{Mass\ of\ solvent\ in\ kg}

Mass of solvent (toluene) = 15.0 g = 0.015 kg

0.26 = \frac{Mole\ of\ compound}{0.015}

Moles of compound = 0.015 × 0.26 = 0.00389 mol

Mol = \frac{Mass\ in\ g}{Molecular\ weight}

Mass of the compound = 1.450 g

Molecular\ weight = \frac{Mass\ in\ g}{Moles}

Molecular weight = \frac{1.450}{0.00389} = 372.13\ g/mol

4 0
3 years ago
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