The enthalpy of fusion of ice is 330,000 J/kg. If I have a 1 kg sample, how much energy is needed to melt all of it?

2 answers:

8 0

Answer:

C. 330,000 J

Explanation:

Latent heat = mass × specific latent heat

q = mL

Given m = 1 kg and L = 330,000 J/kg:

q = (1 kg) (330,000 J/kg)

q = 330,000 J

6 0

Answer:

C. 330,000 J

Explanation:

The enthalpy of fusion of ice is 330,000 J/kg. If someone has a 1 kg sample, they will need 330,000 J energy in order to melt all of it.

(1 kg) (330,000 J/kg)

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Amiraneli [1.4K]

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3 years ago

Irina-Kira [14]

Answer:

2.30 × 10⁻⁸ N if the two electrons are in a vacuum.

Explanation:

The Coulomb's Law gives the size of the electrostatic force $F$ between two charged objects:

$\displaystyle F = -\frac{k\cdot q_1 \cdot q_2}{r^{2}}$ ,

where

$k$ is coulomb's constant. $k = 8.99\times 10^{8}\;\text{N}\cdot\text{m}^{2}\cdot\text{C}^{-2}$ in vacuum.
$q_1$ and $q_2$ are the signed charge of the objects.
$r$ is the distance between the two objects.

For the two electrons:

$\displaystyle F = -\frac{k\cdot q_1 \cdot q_2}{r^{2}} = -\frac{8.99\times 10^{8}\times (1.60\times 10^{-19})^{2}}{(1\times 10^{-10})^{2}} = 2.30\times 10^{-8}\;\text{N}$ .