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3 years ago

The enthalpy of fusion of ice is 330,000 J/kg. If I have a 1 kg sample, how much energy is needed to melt all of it?

Physics

2 answers:

EleoNora [17]3 years ago

8 0

Answer:

C. 330,000 J

Explanation:

Latent heat = mass × specific latent heat

q = mL

Given m = 1 kg and L = 330,000 J/kg:

q = (1 kg) (330,000 J/kg)

q = 330,000 J

Anestetic [448]3 years ago

6 0

Answer:

C. 330,000 J

Explanation:

The enthalpy of fusion of ice is 330,000 J/kg. If someone has a 1 kg sample, they will need 330,000 J energy in order to melt all of it.

(1 kg) (330,000 J/kg)

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What component of a longitudinal sound wave is analogous to a trough of a transverse wave?

anzhelika [568]

Explanation:

There are two components of a longitudinal sound wave which are compression and rarefaction. Similarly, there are two components of the transverse wave, the crest, and trough.

The crest of a wave is defined as the part that has a maximum value of displacement while the trough is defined as the part which corresponds to minimum displacement.

While compression is that space where the particles are close together while the rarefaction is that space where the particles are far apart from each other.

So, the refraction or the rarefied part of a longitudinal sound wave is analogous to a trough of a transverse wave.

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3 years ago

What is the IMA of the following pulley system? 34567

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Answer:

IMA of given system = $\frac{F_{r} }{F_{e} }$

Explanation:

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Its mathematical reference would be:

IMA = $\frac{F_{r} }{F_{e} }$

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3 years ago

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The half-life of Co-55 is 175 hours. How much of a 4000 g of Cobalt-55 sample would be left after 525 hours?

Harrizon [31]

We know that whatever amount we start with, half of it decays and forms atoms of other elements in 175 hours. So in order to figure out how much is left after 525 hours, we'll need to know how many half-lifes pass in that amount of time.

Well, (525 divided by 175) is exactly 3 half-lifes. So this will be easy.

-- After 1 half-life . . .

. . . . . 50% decays, 50% is still there.

-- After the 2nd half-life . . .

. . . . . (half of the leftover 50%) = another 25% decays, 25% is left.

-- After the 3rd half-life . . .

. . . . . (half of the leftover 25%) = another 12.5% decays, 12.5% is left.

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============================================

Another way:

After 1 half-life, 1/2 is left.

After 2 half-lifes, 1/4 is left.

After 3 half-lifes, 1/8 is left.

1/8 of 4,000g = (4,000g/8) = 500 g .

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