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slega [8]
3 years ago
6

A circuit is built based on this circuit diagram. What is the equivalent resistance of the circuit?

Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
7 0
The three resistors are connected to the same points of the circuit, so they are in parallel configuration. The equivalent resistance of 3 resistors in parallel is given by:
\frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}+ \frac{1}{R_3}
If we plug the values of the resistances into the formula, we find
\frac{1}{R_{eq}}= \frac{1}{3.0 \Omega}+ \frac{1}{6.0 \Omega}+ \frac{1}{9.0 \Omega}= \frac{6+3+2}{18.0 \Omega} = \frac{11}{18.0 \Omega}
From which we find the equivalent resistance:
R_{eq} =  \frac{18.0}{11} \Omega =1.6 \Omega

So, the correct answer is B.
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