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Sphinxa [80]
3 years ago
14

quizket Which of the following incorrectly describes mechanisms of CO2 transport? Group of answer choices just over 20% of CO2 i

s carried in the form of carbaminohemoglobin as bicarbonate ions in plasma attached to the heme part of hemoglobin 7-10% of CO2 is dissolved directly into the plasma
Chemistry
1 answer:
Lyrx [107]3 years ago
4 0

Answer:

Attached to the heme part of hemoglobin.

Explanation:

These 3 statements are correct about CO2 transport:

1) Hemoglobin or Hb is known as a protein that is found in RBCs that carries CO2 to the lungs and O2 to cells. CO2 is carried by Hb as carbamino-hemoglobin. Binding of CO2 to Hb occurs because in the tissues the pO2 is low and pCO2 is high. CO2 and O2 combine with Hb to form Carbaminohaemoglobin. So, 20% of CO2 is carried in the form of carbamino-hemoglobin.

2) The enzyme known as carbonic anhydrase catalyzes a reaction in the RBC, where CO2 and H2O are converted into bicarbonate and hydrogen ion and in the tissues, bicarbonate diffuses out of the RBC into the plasma, where it works as a very important pH buffer.

4) 1st, CO2 is more soluble in blood than O2. About 5-7% of all CO2 is dissolved in the plasma. 2nd, CO2 can bind to plasma proteins or can enter RBC and bind to Hb. This form transports about 10% of the CO2.

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Consider the reaction
SOVA2 [1]

Answer :

(a) The average rate will be:

\frac{d[Br_2]}{dt}=9.36\times 10^{-5}M/s

(b) The average rate will be:

\frac{d[H^+]}{dt}=1.87\times 10^{-4}M/s

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

5Br^-(aq)+BrO_3^-(aq)+6H^+(aq)\rightarrow 3Br_2(aq)+3H_2O(l)

The expression for rate of reaction :

\text{Rate of disappearance of }Br^-=-\frac{1}{5}\frac{d[Br^-]}{dt}

\text{Rate of disappearance of }BrO_3^-=-\frac{d[BrO_3^-]}{dt}

\text{Rate of disappearance of }H^+=-\frac{1}{6}\frac{d[H^+]}{dt}

\text{Rate of formation of }Br_2=+\frac{1}{3}\frac{d[Br_2]}{dt}

\text{Rate of formation of }H_2O=+\frac{1}{3}\frac{d[H_2O]}{dt}

Thus, the rate of reaction will be:

\text{Rate of reaction}=-\frac{1}{5}\frac{d[Br^-]}{dt}=-\frac{d[BrO_3^-]}{dt}=-\frac{1}{6}\frac{d[H^+]}{dt}=+\frac{1}{3}\frac{d[Br_2]}{dt}=+\frac{1}{3}\frac{d[H_2O]}{dt}

<u>Part (a) :</u>

<u>Given:</u>

\frac{1}{5}\frac{d[Br^-]}{dt}=1.56\times 10^{-4}M/s

As,  

-\frac{1}{5}\frac{d[Br^-]}{dt}=+\frac{1}{3}\frac{d[Br_2]}{dt}

and,

\frac{d[Br_2]}{dt}=\frac{3}{5}\frac{d[Br^-]}{dt}

\frac{d[Br_2]}{dt}=\frac{3}{5}\times 1.56\times 10^{-4}M/s

\frac{d[Br_2]}{dt}=9.36\times 10^{-5}M/s

<u>Part (b) :</u>

<u>Given:</u>

\frac{1}{5}\frac{d[Br^-]}{dt}=1.56\times 10^{-4}M/s

As,  

-\frac{1}{5}\frac{d[Br^-]}{dt}=-\frac{1}{6}\frac{d[H^+]}{dt}

and,

-\frac{1}{6}\frac{d[H^+]}{dt}=\frac{3}{5}\frac{d[Br^-]}{dt}

\frac{d[H^+]}{dt}=\frac{6}{5}\times 1.56\times 10^{-4}M/s

\frac{d[H^+]}{dt}=1.87\times 10^{-4}M/s

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Which would most likely result in low oxygen levels in the blood?
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Answer:

the person recieving low oxygen by haveing trouble breathing

Explanation:

5 0
3 years ago
Balancing chemical equations
mojhsa [17]

<span>2H2 + O2 → 2H2O</span>

<span>
</span>

<span>okay???</span>

<span>
</span>

4 0
4 years ago
If the amount of Adams if each type on the left and right sides of a reaction difference what must be done to balance it
Ivanshal [37]

Hey there,

Your answer would be

Coefficients are placed in front of the reactants and/or products

Hope this helps,

<h2>- <em>Mr. Helpful</em></h2>

8 0
3 years ago
Name one other organ system that would be affected if it had no marrow.Explain?
muminat
It can possible be you're arteries or also you're intestines with is large and small.

6 0
3 years ago
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